There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ 2sin(x)Icos(x)I + v*3cos(2)x\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 2I^{2}sin(x)cos(x) + 3vxcos(2)\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 2I^{2}sin(x)cos(x) + 3vxcos(2)\right)}{dx}\\=&2I^{2}cos(x)cos(x) + 2I^{2}sin(x)*-sin(x) + 3vcos(2) + 3vx*-sin(2)*0\\=&2I^{2}cos^{2}(x) - 2I^{2}sin^{2}(x) + 3vcos(2)\\ \end{split}\end{equation} \]

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