There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ -2{x}^{3} + 39{x}^{2} - 240x + 11\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = -2x^{3} + 39x^{2} - 240x + 11\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( -2x^{3} + 39x^{2} - 240x + 11\right)}{dx}\\=&-2*3x^{2} + 39*2x - 240 + 0\\=&-6x^{2} + 78x - 240\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( -6x^{2} + 78x - 240\right)}{dx}\\=&-6*2x + 78 + 0\\=&-12x + 78\\ \end{split}\end{equation} \]

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