There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ (0.75x + 1)log_{2}^{0.75x + 1}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 0.75xlog_{2}^{0.75x + 1} + log_{2}^{0.75x + 1}\right)}{dx}\\=&0.75log_{2}^{0.75x + 1} + 0.75x(\frac{(\frac{(0.75 + 0)}{(0.75x + 1)} - \frac{(0)log_{2}^{0.75x + 1}}{(2)})}{(ln(2))}) + (\frac{(\frac{(0.75 + 0)}{(0.75x + 1)} - \frac{(0)log_{2}^{0.75x + 1}}{(2)})}{(ln(2))})\\=&0.75log_{2}^{0.75x + 1} + \frac{0.5625x}{(0.75x + 1)ln(2)} + \frac{0.75}{(0.75x + 1)ln(2)}\\ \end{split}\end{equation} \]

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