There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ arctan(x) - \frac{x}{(1 + ax)}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = arctan(x) - \frac{x}{(ax + 1)}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( arctan(x) - \frac{x}{(ax + 1)}\right)}{dx}\\=&(\frac{(1)}{(1 + (x)^{2})}) - (\frac{-(a + 0)}{(ax + 1)^{2}})x - \frac{1}{(ax + 1)}\\=&\frac{ax}{(ax + 1)^{2}} + \frac{1}{(x^{2} + 1)} - \frac{1}{(ax + 1)}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( \frac{ax}{(ax + 1)^{2}} + \frac{1}{(x^{2} + 1)} - \frac{1}{(ax + 1)}\right)}{dx}\\=&(\frac{-2(a + 0)}{(ax + 1)^{3}})ax + \frac{a}{(ax + 1)^{2}} + (\frac{-(2x + 0)}{(x^{2} + 1)^{2}}) - (\frac{-(a + 0)}{(ax + 1)^{2}})\\=& - \frac{2a^{2}x}{(ax + 1)^{3}} + \frac{2a}{(ax + 1)^{2}} - \frac{2x}{(x^{2} + 1)^{2}}\\ \end{split}\end{equation} \]

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