There are 1 questions in this calculation: for each question, the 2 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ second\ derivative\ of\ function\ sqrt(\frac{(1 - x)}{(1 + x)})\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = sqrt(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( sqrt(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})\right)}{dx}\\=&\frac{(-(\frac{-(1 + 0)}{(x + 1)^{2}})x - \frac{1}{(x + 1)} + (\frac{-(1 + 0)}{(x + 1)^{2}}))*\frac{1}{2}}{(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}}\\=&\frac{x}{2(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{2(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{2(x + 1)(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}}\\\\ &\color{blue}{The\ second\ derivative\ of\ function:} \\&\frac{d\left( \frac{x}{2(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{2(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{2(x + 1)(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}}\right)}{dx}\\=&\frac{(\frac{-2(1 + 0)}{(x + 1)^{3}})x}{2(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} + \frac{(\frac{\frac{-1}{2}(-(\frac{-(1 + 0)}{(x + 1)^{2}})x - \frac{1}{(x + 1)} + (\frac{-(1 + 0)}{(x + 1)^{2}}))}{(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}})x}{2(x + 1)^{2}} + \frac{1}{2(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{(\frac{-2(1 + 0)}{(x + 1)^{3}})}{2(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{(\frac{\frac{-1}{2}(-(\frac{-(1 + 0)}{(x + 1)^{2}})x - \frac{1}{(x + 1)} + (\frac{-(1 + 0)}{(x + 1)^{2}}))}{(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}})}{2(x + 1)^{2}} - \frac{(\frac{-(1 + 0)}{(x + 1)^{2}})}{2(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{(\frac{\frac{-1}{2}(-(\frac{-(1 + 0)}{(x + 1)^{2}})x - \frac{1}{(x + 1)} + (\frac{-(1 + 0)}{(x + 1)^{2}}))}{(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}})}{2(x + 1)}\\=&\frac{-x}{(x + 1)^{3}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{x^{2}}{4(x + 1)^{4}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}} + \frac{x}{4(x + 1)^{3}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}} + \frac{x}{2(x + 1)^{4}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}} + \frac{x}{4(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}(x + 1)^{3}} + \frac{1}{(x + 1)^{2}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{4(x + 1)^{4}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}} + \frac{1}{(x + 1)^{3}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{1}{2}}} - \frac{1}{4(x + 1)^{3}(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}} - \frac{1}{4(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}(x + 1)^{3}} - \frac{1}{4(\frac{-x}{(x + 1)} + \frac{1}{(x + 1)})^{\frac{3}{2}}(x + 1)^{2}}\\ \end{split}\end{equation} \]Your problem has not been solved here? Please take a look at the hot problems !