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==equ==
Unary equation
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==cal==
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==LiAl==
Determinant
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==der==
Derivative function
==img==
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==que==
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质量为$3kg$的水受到的重力多大$?$
解:
因为物体受到的重力与质量成正比,受到的重力$G$与质量$m$的关系式为: $$ G=mg $$ 所以,$m=3kg$的水受到的重力$G$为: $$ \begin{align} G=&mg\\ =&3kg \times 9.8N/kg\\ =&29.4N \end{align} $$ 即,
$3kg$的水受到的重力为$29.4N$
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