Hot issues：
This module collects the frequently encountered and difficult problems for reference only.
This module collects the frequently encountered and difficult problems for reference only.
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质量为$3kg$的水受到的重力多大$?$
因为物体受到的重力与质量成正比，受到的重力$G$与质量$m$的关系式为： $$ G=mg $$ 所以，$m=3kg$的水受到的重力$G$为： $$ \begin{align} G=&mg\\ =&3kg \times 9.8N/kg\\ =&29.4N \end{align} $$ 即，$3kg$的水受到的重力为$29.4N$