总述:本次共解1题。其中
☆方程1题
〖 1/1方程〗
作业:求方程 (x+1)(x+2)-(x-3)(x+6) = 0 的解.
题型:方程
解:原方程:| | ( | x | + | 1 | ) | ( | x | + | 2 | ) | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) | = | 0 |
去掉方程左边的括号:
| 方程左边 = | x | ( | x | + | 2 | ) | + | 1 | ( | x | + | 2 | ) | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) |
| = | x | x | + | x | × | 2 | + | 1 | ( | x | + | 2 | ) | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) |
| = | x | x | + | 2 | x | + | 1 | x | + | 1 | × | 2 | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) |
| = | x | x | + | 2 | x | + | 1 | x | + | 2 | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) |
| = | x | x | + | 3 | x | + | 2 | − | ( | x | − | 3 | ) | ( | x | + | 6 | ) |
| = | x | x | + | 3 | x | + | 2 | − | x | ( | x | + | 6 | ) | + | 3 | ( | x | + | 6 | ) |
| = | x | x | + | 3 | x | + | 2 | − | x | x | − | x | × | 6 | + | 3 | ( | x | + | 6 | ) |
| = | x | x | − | 3 | x | + | 2 | − | x | x | + | 3 | ( | x | + | 6 | ) |
| = | x | x | − | 3 | x | + | 2 | − | x | x | + | 3 | x | + | 3 | × | 6 |
| = | x | x | − | 3 | x | + | 2 | − | x | x | + | 3 | x | + | 18 |
方程化为:
本方程没有实数解!
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