Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (x-0.08)/(0.07-0.08) = (4-3.9927)/(4-3.9927)/(4.002-3.9927) .
    Question type: Equation
    Solution:Original question:
     ( x
2
25
) ÷ (
7
100
2
25
) = (4
39927
10000
) ÷ (4
39927
10000
) ÷ (
2001
500
39927
10000
)
     Multiply both sides of the equation by:(
7
100
2
25
) ,  (4
39927
10000
)
     ( x
2
25
)(4
39927
10000
) = (4
39927
10000
) ÷ (
2001
500
39927
10000
) × (
7
100
2
25
)
    Remove a bracket on the left of the equation::
      x (4
39927
10000
)
2
25
(4
39927
10000
) = (4
39927
10000
) ÷ (
2001
500
39927
10000
) × (
7
100
2
25
)
    Remove a bracket on the right of the equation::
      x (4
39927
10000
)
2
25
(4
39927
10000
) = 4 ÷ (
2001
500
39927
10000
) × (
7
100
2
25
)
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)
     Multiply both sides of the equation by:(
2001
500
39927
10000
)
      x (4
39927
10000
)(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
) = 4(
7
100
2
25
)
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the left of the equation:
      x × 4(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
) = 4(
7
100
2
25
)
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the right of the equation::
      x × 4(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
) = 4 ×
7
100
4 ×
2
25
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)(
2001
500
39927
10000
)
    The equation is reduced to :
      x × 4(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
) =
7
25
8
25
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)(
2001
500
39927
10000
)
    The equation is reduced to :
      x × 4(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
) = -
1
25
39927
10000
÷ (
2001
500
39927
10000
) × (
7
100
2
25
)(
2001
500
39927
10000
)
     Multiply both sides of the equation by:(
2001
500
39927
10000
)
      x × 4(
2001
500
39927
10000
)(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
)
2
25
(4
39927
10000
)(
2001
500
39927
10000
)(
2001
500
39927
10000
) = -
1
25
(
2001
500
39927
10000
)
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the left of the equation:
      x × 4 ×
2001
500
(
2001
500
39927
10000
) x × 4 ×
39927
10000
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
) = -
1
25
(
2001
500
39927
10000
)
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the right of the equation::
      x × 4 ×
2001
500
(
2001
500
39927
10000
) x × 4 ×
39927
10000
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
) = -
1
25
×
2001
500
+
1
25
×
39927
10000
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    The equation is reduced to :
      x ×
2001
125
(
2001
500
39927
10000
) x ×
39927
2500
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
)
2
25
(4
39927
10000
) = -
2001
12500
+
39927
250000
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    The equation is reduced to :
      x ×
2001
125
(
2001
500
39927
10000
) x ×
39927
2500
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
)
2
25
(4
39927
10000
) = -
93
250000
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the left of the equation:
      x ×
2001
125
×
2001
500
x ×
2001
125
×
39927
10000
x ×
39927
2500
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
) = -
93
250000
39927
10000
(
7
100
2
25
)(
2001
500
39927
10000
)
    Remove a bracket on the right of the equation::
      x ×
2001
125
×
2001
500
x ×
2001
125
×
39927
10000
x ×
39927
2500
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
) = -
93
250000
39927
10000
×
7
100
(
2001
500
39927
10000
) +
39927
10000
×
2
25
(
2001
500
39927
10000
)
    The equation is reduced to :
      x ×
4004001
62500
x ×
79893927
1250000
x ×
39927
2500
(
2001
500
39927
10000
) x ×
39927
10000
(
2001
500
39927
10000
)(
2001
500
39927
10000
)
2
25
= -
93
250000
279489
1000000
(
2001
500
39927
10000
) +
39927
125000
(
2001
500
39927
10000
)

    
        x≈-0.995269 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。