detailed information: The input equation set is:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | 120 | A | + | | 135 | B | + | | 95 | C | + | | 70 | D | = | | 115 | | (2) |
| | 135 | A | + | | 90 | B | + | | 125 | C | + | | 100 | D | = | | 120 | | (3) |
| | 130 | A | + | | 135 | B | + | | 125 | C | + | | 115 | D | = | | 130 | | (4) |
| Question solving process:
Multiply both sides of equation (1) by 4 Divide the two sides of equation (1) by 3, the equation can be obtained: | | 120 | A | + | | | 400 3 | B | + | | 100 | C | + | | 80 | D | = | | 120 | (5) | , then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | | 135 | A | + | | 90 | B | + | | 125 | C | + | | 100 | D | = | | 120 | | (3) |
| | 130 | A | + | | 135 | B | + | | 125 | C | + | | 115 | D | = | | 130 | | (4) |
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Multiply both sides of equation (1) by 3 Divide the two sides of equation (1) by 2, the equation can be obtained: | | 135 | A | + | | 150 | B | + | | | 225 2 | C | + | | 90 | D | = | | 135 | (6) | , then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | -60 | B | + | | | 25 2 | C | + | | 10 | D | = | | -15 | | (3) |
| | 130 | A | + | | 135 | B | + | | 125 | C | + | | 115 | D | = | | 130 | | (4) |
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Multiply both sides of equation (1) by 13 Divide the two sides of equation (1) by 9, the equation can be obtained: | | 130 | A | + | | | 1300 9 | B | + | | | 325 3 | C | + | | | 260 3 | D | = | | 130 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | -60 | B | + | | | 25 2 | C | + | | 10 | D | = | | -15 | | (3) |
| - | 85 9 | B | + | | | 50 3 | C | + | | | 85 3 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 36, the equation can be obtained: | | 60 | B | | -180 | C | | -360 | D | = | | -180 | (8) | , then add the two sides of equation (8) to both sides of equation (3), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | | - | 85 9 | B | + | | | 50 3 | C | + | | | 85 3 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 17 Divide the two sides of equation (2) by 3, the equation can be obtained: | | | 85 9 | B | | - | 85 3 | C | | - | 170 3 | D | = | | - | 85 3 | (9) | , then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
| | | - | 35 3 | C | | - | 85 3 | D | = | | - | 85 3 | | (4) |
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Multiply both sides of equation (3) by 14 Divide the two sides of equation (3) by 201, the equation can be obtained: | - | 2345 201 | C | | - | 4900 201 | D | = | | - | 910 67 | (10) | , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
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Multiply both sides of equation (4) by 4690 Divide both sides of equation (4) by 53, get the equation:, then subtract both sides of equation (11) from both sides of equation (3), get the equation:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
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Multiply both sides of equation (4) by 134 Divide both sides of equation (4) by 53, get the equation:, then subtract both sides of equation (12) from both sides of equation (2), get the equation:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | + | | 60 | D | = | | 90 | | (1) |
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Multiply both sides of equation (4) by 804 Divide both sides of equation (4) by 53, get the equation:, then add the two sides of equation (13) to both sides of equation (1), get the equation:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | = | | - | 7090 53 | | (1) |
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Multiply both sides of equation (3) by 2 Divide both sides of equation (3) by 67, get the equation:, then subtract both sides of equation (14) from both sides of equation (2), get the equation:
| | | | 90 | A | + | | 100 | B | + | | 75 | C | = | | - | 7090 53 | | (1) |
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Multiply both sides of equation (3) by 30 Divide both sides of equation (3) by 67, get the equation:, then add the two sides of equation (15) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 60, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |