detailed information: The input equation set is: Question solving process:
Subtract both sides of equation (1) from both sides of equation (3) ,the equations are reduced to:
Multiply both sides of equation (1) by 2, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (1) by 8, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (6), the equations are reduced to:
 | | | | | | | | | -8 | B | + | | 16 | C | | -8 | D | | -4 | E | = | | 20 | | (6) |
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Add both sides of equation (2) to both sides of equation (3) ,the equations are reduced to:
 | | | | | | | | | -8 | B | + | | 16 | C | | -8 | D | | -4 | E | = | | 20 | | (6) |
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Multiply both sides of equation (2) by 12, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
 | | | | | | | | | -8 | B | + | | 16 | C | | -8 | D | | -4 | E | = | | 20 | | (6) |
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Multiply both sides of equation (2) by 8, the equation can be obtained: , then add the two sides of equation (10) to both sides of equation (6), the equations are reduced to:
交After the exchange of equation (3) and equation (4), the equation system becomes:
Multiply both sides of equation (3) by 2 Divide the two sides of equation (3) by 5, the equation can be obtained: | | -8 | C | | - | 4 5 | D | | - | 24 5 | E | = | | -16 | (11) | , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (3) by 2 Divide the two sides of equation (3) by 5, the equation can be obtained: | | -8 | C | | - | 4 5 | D | | - | 24 5 | E | = | | -16 | (12) | , then add the two sides of equation (12) to both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (4) by 4 Divide the two sides of equation (4) by 5, the equation can be obtained: | | - | 4 5 | D | | - | 4 5 | E | + | | | 4 5 | F | = | | 0 | (13) | , then subtract both sides of equation (13) from both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (4) by 44 Divide the two sides of equation (4) by 5, the equation can be obtained: | | - | 44 5 | D | | - | 44 5 | E | + | | | 44 5 | F | = | | 0 | (14) | , then subtract both sides of equation (14) from both sides of equation (6), the equations are reduced to:
Subtract both sides of equation (5) from both sides of equation (6) ,the equations are reduced to:
Divide both sides of equation (5) by 8, get the equation:, then subtract both sides of equation (15) from both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 2, get the equation:, then subtract both sides of equation (16) from both sides of equation (3), get the equation:
 | | | | | | -20 | C | | -2 | D | + | | | 66 5 | F | = | | -46 | | (3) |
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Divide both sides of equation (5) by 8, get the equation:, then subtract both sides of equation (17) from both sides of equation (2), get the equation:
 | | | | | | -20 | C | | -2 | D | + | | | 66 5 | F | = | | -46 | | (3) |
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Multiply both sides of equation (4) by 2, get the equation:, then subtract both sides of equation (18) from both sides of equation (3), get the equation:
Add both sides of equation (4) to both sides of equation (1), get the equation:
Divide both sides of equation (3) by 20, get the equation:, then subtract both sides of equation (19) from both sides of equation (2), get the equation:
Subtract both sides of equation (2) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: F are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |