Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality -4000-1000/(1+x)+600(1-(1+x)^29)/（1-x）(1+x)^2 >0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        -4000 - 1000 / ( 1 + x ) + 600 * ( 1 - ( 1 + x ) ^ 29 ) / ( 1 - x ) * ( 1 + x ) ^ 2 >0         (1)
        From the definition field of divisor
         1 + x ≠ 0        (2 )
        From the definition field of divisor
         1 - x ≠ 0        (3 )

---

    From inequality(1)：
         x < -2.090553 或  -1.251054 < x < -1 或  x ＞ 1
    From inequality(2)：
         x < -1 或  x ＞ -1
    From inequality(3)：
         x < 1 或  x ＞ 1

---

    From inequalities (1) and (2)
         x < -2.090553 或  -1.251054 < x < -1 或  x ＞ 1    (4)
    From inequalities (3) and (4)
         x < -2.090553 或  -1.251054 < x < -1 或  x ＞ 1    (5)

---

    The final solution set is :
         x < -2.090553 或  -1.251054 < x < -1 或  x ＞ 1

Your problem has not been solved here? Please take a look at the  hot problems ！