Mathematics
语言：中文
Language:English

current location：Equations > Multivariate equations > Answer
Detailed information：
The input equation set is:
 28x + 7y = 105    (1)
 55x + 11y = 253    (2)
Question solving process:

Multiply both sides of equation (1) by 55
Divide the two sides of equation (1) by 28, the equation can be obtained:
         55x + 
55
4
y = 
825
4
    (3)
, then subtract both sides of equation (3) from both sides of equation (2), the equations are reduced to:
 28x + 7y = 105    (1)
- 
11
4
y = 
187
4
    (2)

Multiply both sides of equation (2) by 28
Divide both sides of equation (2) by 11, get the equation：
        -7y = 119    (4)
, then add the two sides of equation (4) to both sides of equation (1), get the equation：
 28x = 224    (1)
- 
11
4
y = 
187
4
    (2)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 x = 8    (1)
 y = -17    (2)


Therefore, the solution of the equation set is:
x = 8
y = -17

解方程组的详细方法请参阅：《多元一次方程组的解法》
Return