Mathematics
语言：中文
Language:English

current location：Equations > Multivariate equations > Answer
Detailed information：
The input equation set is:
 A + 2B + 2C + 2D + 2E = 322    (1)
 A + 2B + 3C + 4D + 5E = 999    (2)
0 = 0    (3)
0 = 0    (4)
0 = 0    (5)
Question solving process:

Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 A + 2B + 2C + 2D + 2E = 322    (1)
 C + 2D + 3E = 677    (2)
0 = 0    (3)
0 = 0    (4)
0 = 0    (5)

Multiply both sides of equation (2) by 2, get the equation：
         2B + 2C + 4D + 6E = 1354    (6)
, then subtract both sides of equation (6) from both sides of equation (1), get the equation：
 A + 2B -2D -4E = -1032    (1)
 C + 2D + 3E = 677    (2)
0 = 0    (3)
0 = 0    (4)
0 = 0    (5)


Therefore, the solution of the equation set is:
A = -1032 - 2B + 2D + 4E
C = 677 - 2D - 3E

Where:  B, D, E are arbitrary constants.
解方程组的详细方法请参阅：《多元一次方程组的解法》
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