本次共计算 1 个题目:每一题对 x 求 2 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数{(e^{2}x - ln(x + 1))}^{2} 关于 x 的 2 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = - 2xe^{2}ln(x + 1) + x^{2}e^{{2}*{2}} + ln^{2}(x + 1)\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( - 2xe^{2}ln(x + 1) + x^{2}e^{{2}*{2}} + ln^{2}(x + 1)\right)}{dx}\\=& - 2e^{2}ln(x + 1) - 2xe^{2}*0ln(x + 1) - \frac{2xe^{2}(1 + 0)}{(x + 1)} + 2xe^{{2}*{2}} + x^{2}*2e^{2}e^{2}*0 + \frac{2ln(x + 1)(1 + 0)}{(x + 1)}\\=& - 2e^{2}ln(x + 1) - \frac{2xe^{2}}{(x + 1)} + 2xe^{{2}*{2}} + \frac{2ln(x + 1)}{(x + 1)}\\\\ &\color{blue}{函数的第 2 阶导数:} \\&\frac{d\left( - 2e^{2}ln(x + 1) - \frac{2xe^{2}}{(x + 1)} + 2xe^{{2}*{2}} + \frac{2ln(x + 1)}{(x + 1)}\right)}{dx}\\=& - 2e^{2}*0ln(x + 1) - \frac{2e^{2}(1 + 0)}{(x + 1)} - 2(\frac{-(1 + 0)}{(x + 1)^{2}})xe^{2} - \frac{2e^{2}}{(x + 1)} - \frac{2xe^{2}*0}{(x + 1)} + 2e^{{2}*{2}} + 2x*2e^{2}e^{2}*0 + 2(\frac{-(1 + 0)}{(x + 1)^{2}})ln(x + 1) + \frac{2(1 + 0)}{(x + 1)(x + 1)}\\=& - \frac{4e^{2}}{(x + 1)} + \frac{2xe^{2}}{(x + 1)^{2}} + 2e^{{2}*{2}} - \frac{2ln(x + 1)}{(x + 1)^{2}} + \frac{2}{(x + 1)^{2}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!