本次共计算 1 个题目:每一题对 x 求 1 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数\frac{-a(\frac{15.96x}{n} + 2)}{(c*2{x}^{3}{(1 + \frac{5.32x}{n})}^{2})} 关于 x 的 1 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{-7.98a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{2}} - \frac{a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)cx^{3}}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{-7.98a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{2}} - \frac{a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)cx^{3}}\right)}{dx}\\=&\frac{-7.98(\frac{-(\frac{5.32}{n} + 0)}{(\frac{5.32x}{n} + 1)^{2}})a}{(\frac{5.32x}{n} + 1)ncx^{2}} - \frac{7.98(\frac{-(\frac{5.32}{n} + 0)}{(\frac{5.32x}{n} + 1)^{2}})a}{(\frac{5.32x}{n} + 1)ncx^{2}} - \frac{7.98a*-2}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{3}} - \frac{(\frac{-(\frac{5.32}{n} + 0)}{(\frac{5.32x}{n} + 1)^{2}})a}{(\frac{5.32x}{n} + 1)cx^{3}} - \frac{(\frac{-(\frac{5.32}{n} + 0)}{(\frac{5.32x}{n} + 1)^{2}})a}{(\frac{5.32x}{n} + 1)cx^{3}} - \frac{a*-3}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)cx^{4}}\\=&\frac{42.4536a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)n^{2}cx^{2}} + \frac{42.4536a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)n^{2}cx^{2}} + \frac{15.96a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{3}} + \frac{5.32a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{3}} + \frac{5.32a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)ncx^{3}} + \frac{3a}{(\frac{5.32x}{n} + 1)(\frac{5.32x}{n} + 1)cx^{4}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!