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〖1/1算式〗
作业:求算式 1/(2*0.0179^(1/2))*(8.209/29.53)^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2) 的值.
题型:数学计算
解:
1/(2*0.0179^(1/2))*(8.209/29.53)^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2)
=1/(2*0.0179^0.5)*(8.209/29.53)^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2)
=1/0.267582*(8.209/29.53)^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2)
=1/0.267582*0.277988^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2)
=1/0.267582*0.277988^0.333333*(1+(125*0.0179+0.1)*0.5^1.2)
=1/0.267582*0.277988^0.333333*(1+2.3375*0.5^1.2)
=1/0.267582*0.277988^0.333333*2.017456
=1/0.267582*0.652642775624044*2.017456
=3.737172*0.652642775624044*2.017456
=2.439038*2.017456
=4.920652 答案:1/(2*0.0179^(1/2))*(8.209/29.53)^(1/3)*(1+(125*0.0179+0.1)*0.5^1.2)=4.920652你的问题在这里没有得到解决?请到 热门难题 里面看看吧!