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〖1/1算式〗
作业:求算式 1.2*(7.55/8.209)^(2/3)*(1-3245.022/(2*(6490.044+4004)))*1800/1619.073 的值.
题型:数学计算
解:
1.2*(7.55/8.209)^(2/3)*(1-3245.022/(2*(6490.044+4004)))*1800/1619.073
=1.2*0.919722^(2/3)*(1-3245.022/(2*(6490.044+4004)))*1800/1619.073
=1.2*0.919722^0.666667*(1-3245.022/(2*(6490.044+4004)))*1800/1619.073
=1.2*0.919722^0.666667*(1-3245.022/(2*10494.044))*1800/1619.073
=1.2*0.919722^0.666667*(1-3245.022/20988.088)*1800/1619.073
=1.2*0.919722^0.666667*0.845387*1800/1619.073
=1.2*0.945738432189993*0.845387*1800/1619.073
=1.134886*0.845387*1800/1619.073
=0.959418*1800/1619.073
=1726.9524/1619.073
=1.06663 答案:1.2*(7.55/8.209)^(2/3)*(1-3245.022/(2*(6490.044+4004)))*1800/1619.073=1.06663你的问题在这里没有得到解决?请到 热门难题 里面看看吧!