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〖1/1算式〗
作业:求算式 0.5*(22*10^-3)*0.24*0.24*(3.1415926/3)*(3.1415926/3) 的值.
题型:数学计算
解:
0.5*(22*10^-3)*0.24*0.24*(3.1415926/3)*(3.1415926/3)
=0.5*0.022*0.24*0.24*(3.1415926/3)*(3.1415926/3)
=0.5*0.022*0.24*0.24*1.047198*(3.1415926/3)
=0.5*0.022*0.24*0.24*1.047198*1.047198
=0.011*0.24*0.24*1.047198*1.047198
=0.00264*0.24*1.047198*1.047198
=0.000634*1.047198*1.047198
=0.000664*1.047198
=0.000695 答案:0.5*(22*10^-3)*0.24*0.24*(3.1415926/3)*(3.1415926/3)=0.000695你的问题在这里没有得到解决?请到 热门难题 里面看看吧!