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〖1/1算式〗
作业:求算式 1.2*0.2317*(0.909*ln(319.45/293.15)-8.314/32*ln(0.5075/0.22))+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075) 的值.
题型:数学计算
解:
1.2*0.2317*(0.909*ln(319.45/293.15)-8.314/32*ln(0.5075/0.22))+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075)
=1.2*0.2317*(0.909*ln1.089715-8.314/32*ln(0.5075/0.22))+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075)
=1.2*0.2317*(0.909*ln1.089715-8.314/32*ln2.306818)+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075)
=1.2*0.2317*(-0.139072)+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075)
=1.2*0.2317*(-0.139072)+0.8*(0.909*ln0.879664-8.314/32*ln0.5075)
=1.2*0.2317*(-0.139072)+0.8*0.059674
=0.27804*(-0.139072)+0.8*0.059674
=(-0.038668)+0.8*0.059674
=-0.038668+0.047739
=0.009071 答案:1.2*0.2317*(0.909*ln(319.45/293.15)-8.314/32*ln(0.5075/0.22))+0.8*(0.909*ln(319.45/363.15)-8.314/32*ln0.5075)=0.009071你的问题在这里没有得到解决?请到 热门难题 里面看看吧!