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〖1/1算式〗
作业:求算式 ((210-202.5)^2+(160-202.5)^2+(75-202.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5 的值.
题型:数学计算
解:
((210-202.5)^2+(160-202.5)^2+(75-202.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5
=(7.5^2+(160-202.5)^2+(75-202.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5
=(7.5^2+(-42.5)^2+(75-202.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5
=(7.5^2+(-42.5)^2+(-127.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5
=(7.5^2+(-42.5)^2+(-127.5)^2+77.5^2+(300-202.5)^2+(190-202.5)^2)/5
=(7.5^2+(-42.5)^2+(-127.5)^2+77.5^2+97.5^2+(190-202.5)^2)/5
=(7.5^2+(-42.5)^2+(-127.5)^2+77.5^2+97.5^2+(-12.5)^2)/5
=33787.5/5
=6757.5 答案:((210-202.5)^2+(160-202.5)^2+(75-202.5)^2+(280-202.5)^2+(300-202.5)^2+(190-202.5)^2)/5=6757.5你的问题在这里没有得到解决?请到 热门难题 里面看看吧!