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〖1/1算式〗
作业:求算式 (0.6^2)*((1-9/180)/9)*2242.361+(0.4^2)*((1-6/120)/6)*6757.5 的值.
题型:数学计算
解:
(0.6^2)*((1-9/180)/9)*2242.361+(0.4^2)*((1-6/120)/6)*6757.5
=0.36*((1-9/180)/9)*2242.361+(0.4^2)*((1-6/120)/6)*6757.5
=0.36*(0.95/9)*2242.361+(0.4^2)*((1-6/120)/6)*6757.5
=0.36*0.105556*2242.361+(0.4^2)*((1-6/120)/6)*6757.5
=0.36*0.105556*2242.361+0.16*((1-6/120)/6)*6757.5
=0.36*0.105556*2242.361+0.16*(0.95/6)*6757.5
=0.36*0.105556*2242.361+0.16*0.158333*6757.5
=0.038*2242.361+0.16*0.158333*6757.5
=85.209718+0.16*0.158333*6757.5
=85.209718+0.025333*6757.5
=85.209718+171.187748
=256.397466 答案:(0.6^2)*((1-9/180)/9)*2242.361+(0.4^2)*((1-6/120)/6)*6757.5=256.397466你的问题在这里没有得到解决?请到 热门难题 里面看看吧!