总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 10^(3.5048-(4.079-0.301*(8-1.55))*(-2.5*ln0.9)^(1/6.8713)) 的值.
题型:数学计算
解:
10^(3.5048-(4.079-0.301*(8-1.55))*(-2.5*ln0.9)^(1/6.8713))
=10^(3.5048-(4.079-0.301*6.45)*(-2.5*ln0.9)^(1/6.8713))
=10^(3.5048-2.13755*(-2.5*ln0.9)^(1/6.8713))
=10^(3.5048-2.13755*0.263402^(1/6.8713))
=10^(3.5048-2.13755*0.263402^0.145533)
=10^1.744457
=55.520964244786924 答案:10^(3.5048-(4.079-0.301*(8-1.55))*(-2.5*ln0.9)^(1/6.8713))=55.520964244786924你的问题在这里没有得到解决?请到 热门难题 里面看看吧!