总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 1/12×(0.8)^2×((2×1.6+2.4)*(25.42+23.8-(2×1.6×2.4×0.5×26)/(1.6×2.4))+(25.42-23.8)×2.8) 的值.
    题型：数学计算
    解:
          1/12×(0.8)^2×((2×1.6+2.4)*(25.42+23.8-(2×1.6×2.4×0.5×26)/(1.6×2.4))+(25.42-23.8)×2.8)
        =1/12×0.8^2×((2×1.6+2.4)*(25.42+23.8-(2×1.6×2.4×0.5×26)/(1.6×2.4))+(25.42-23.8)×2.8)
        =1/12×0.8^2×(5.6*(25.42+23.8-(2×1.6×2.4×0.5×26)/(1.6×2.4))+(25.42-23.8)×2.8)
        =1/12×0.8^2×(5.6*(25.42+23.8-99.84/(1.6×2.4))+(25.42-23.8)×2.8)
        =1/12×0.8^2×(5.6*(25.42+23.8-99.84/3.84)+(25.42-23.8)×2.8)
        =1/12×0.8^2×(5.6*23.22+(25.42-23.8)×2.8)
        =1/12×0.8^2×(5.6*23.22+1.62×2.8)
        =1/12×0.8^2×134.568
        =1/12×0.64×134.568
        =0.083333×0.64×134.568
        =0.053333×134.568
        =7.176915
    答案:1/12×(0.8)^2×((2×1.6+2.4)*(25.42+23.8-(2×1.6×2.4×0.5×26)/(1.6×2.4))+(25.42-23.8)×2.8)=7.176915

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