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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 5*(1-0.75x)*2500*(1+2.5x)+4500*7 = (4500*7+2500*5)*[1+(5/11)x] .
    Question type: Equation
    Solution:Original question:
     5(1
3
4
x ) × 2500(1 +
5
2
x ) + 4500 × 7 = (4500 × 7 + 2500 × 5)(1 + (5 ÷ 11) x )
     Left side of the equation = 12500(1
3
4
x )(1 +
5
2
x ) + 31500
    The equation is transformed into :
     12500(1
3
4
x )(1 +
5
2
x ) + 31500 = (4500 × 7 + 2500 × 5)(1 + (5 ÷ 11) x )
    Remove the bracket on the left of the equation:
     Left side of the equation = 12500 × 1(1 +
5
2
x )12500 ×
3
4
x (1 +
5
2
x ) + 31500
                                             = 12500(1 +
5
2
x )9375 x (1 +
5
2
x ) + 31500
                                             = 12500 × 1 + 12500 ×
5
2
x 9375 x (1 +
5
2
x ) + 31500
                                             = 12500 + 31250 x 9375 x (1 +
5
2
x ) + 31500
                                             = 44000 + 31250 x 9375 x (1 +
5
2
x )
                                             = 44000 + 31250 x 9375 x × 19375 x ×
5
2
x
                                             = 44000 + 31250 x 9375 x
46875
2
x x
                                             = 44000 + 21875 x
46875
2
x x
    The equation is transformed into :
     44000 + 21875 x
46875
2
x x = (4500 × 7 + 2500 × 5)(1 + (5 ÷ 11) x )
    Remove the bracket on the right of the equation:
     Right side of the equation = 4500 × 7(1 + (5 ÷ 11) x ) + 2500 × 5(1 + (5 ÷ 11) x )
                                               = 31500(1 + (5 ÷ 11) x ) + 12500(1 + (5 ÷ 11) x )
                                               = 31500 × 1 + 31500(5 ÷ 11) x + 12500(1 + (5 ÷ 11) x )
                                               = 31500 + 31500(5 ÷ 11) x + 12500(1 + (5 ÷ 11) x )
                                               = 31500 + 31500 × 5 ÷ 11 × x + 12500(1 + (5 ÷ 11) x )
                                               = 31500 +
157500
11
x + 12500(1 + (5 ÷ 11) x )
                                               = 31500 +
157500
11
x + 12500 × 1 + 12500(5 ÷ 11) x
                                               = 31500 +
157500
11
x + 12500 + 12500(5 ÷ 11) x
                                               = 44000 +
157500
11
x + 12500(5 ÷ 11) x
                                               = 44000 +
157500
11
x + 12500 × 5 ÷ 11 × x
                                               = 44000 +
157500
11
x +
62500
11
x
                                               = 44000 + 20000 x
    The equation is transformed into :
     44000 + 21875 x
46875
2
x x = 44000 + 20000 x

    After the equation is converted into a general formula, it is converted into:
    ( x +0 )( 25x - 2 )=0
    From
        x + 0 = 0
        25x - 2 = 0

    it is concluded that::
        x1=0
        x2=
2
25
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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