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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 32/5(10-2t)-2t = 18/5(10-2t) .
    Question type: Equation
    Solution:Original question:
     32 ÷ 5 × (102 t )2 t = 18 ÷ 5 × (102 t )
     Left side of the equation =
32
5
(102 t )2 t
    The equation is transformed into :
     
32
5
(102 t )2 t = 18 ÷ 5 × (102 t )
    Remove the bracket on the left of the equation:
     Left side of the equation =
32
5
× 10
32
5
× 2 t 2 t
                                             = 64
64
5
t 2 t
                                             = 64
74
5
t
    The equation is transformed into :
     64
74
5
t = 18 ÷ 5 × (102 t )
     Right side of the equation =
18
5
(102 t )
    The equation is transformed into :
     64
74
5
t =
18
5
(102 t )
    Remove the bracket on the right of the equation:
     Right side of the equation =
18
5
× 10
18
5
× 2 t
                                               = 36
36
5
t
    The equation is transformed into :
     64
74
5
t = 36
36
5
t

    Transposition :
      -
74
5
t +
36
5
t = 3664

    Combine the items on the left of the equation:
      -
38
5
t = 3664

    Combine the items on the right of the equation:
      -
38
5
t = - 28

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     28 =
38
5
t

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
38
5
t = 28

    The coefficient of the unknown number is reduced to 1 :
      t = 28 ÷
38
5
        = 28 ×
5
38
        = 14 ×
5
19

    We obtained :
      t =
70
19
    This is the solution of the equation.

    Convert the result to decimal form :
      t = 3.684211



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