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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation [400*(1+x/100)-50]*[1+(x+2.5)/100] = 378 .
    Question type: Equation
    Solution:Original question:
     (400(1 + x ÷ 100)50)(1 + ( x +
5
2
) ÷ 100) = 378
    Remove the bracket on the left of the equation:
     Left side of the equation = 400(1 + x ÷ 100)(1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400 × 1(1 + ( x +
5
2
) ÷ 100) + 400 x ÷ 100 × (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400(1 + ( x +
5
2
) ÷ 100) + 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400 × 1 + 400( x +
5
2
) ÷ 100 + 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400 + 4( x +
5
2
) + 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400 + 4 x + 4 ×
5
2
+ 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 400 + 4 x + 10 + 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 4 x + 4 x (1 + ( x +
5
2
) ÷ 100)50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 4 x + 4 x × 1 + 4 x ( x +
5
2
) ÷ 10050(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 4 x + 4 x +
1
25
x ( x +
5
2
)50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 8 x +
1
25
x ( x +
5
2
)50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 8 x +
1
25
x x +
1
25
x ×
5
2
50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 + 8 x +
1
25
x x +
1
10
x 50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 +
81
10
x +
1
25
x x 50(1 + ( x +
5
2
) ÷ 100)
                                             = 410 +
81
10
x +
1
25
x x 50 × 150( x +
5
2
) ÷ 100
                                             = 410 +
81
10
x +
1
25
x x 50
1
2
( x +
5
2
)
                                             = 360 +
81
10
x +
1
25
x x
1
2
( x +
5
2
)
                                             = 360 +
81
10
x +
1
25
x x
1
2
x
1
2
×
5
2
                                             = 360 +
81
10
x +
1
25
x x
1
2
x
5
4
                                             =
1435
4
+
38
5
x +
1
25
x x
    The equation is transformed into :
     
1435
4
+
38
5
x +
1
25
x x = 378

    After the equation is converted into a general formula, it is converted into:
    ( 2x + 385 )( 2x - 5 )=0
    From
        2x + 385 = 0
        2x - 5 = 0

    it is concluded that::
        x1=-
385
2
        x2=
5
2
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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