Mathematics
         
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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (3-a)×(200+400a)-(400a+200)×2-24 = 200 .
    Question type: Equation
    Solution:Original question:
     (3 a )(200 + 400 a )(400 a + 200) × 224 = 200
    Remove the bracket on the left of the equation:
     Left side of the equation = 3(200 + 400 a ) a (200 + 400 a )(400 a + 200) × 224
                                             = 3 × 200 + 3 × 400 a a (200 + 400 a )(400 a + 200) × 224
                                             = 600 + 1200 a a (200 + 400 a )(400 a + 200) × 224
                                             = 576 + 1200 a a (200 + 400 a )(400 a + 200) × 2
                                             = 576 + 1200 a a × 200 a × 400 a (400 a + 200) × 2
                                             = 576 + 1000 a a × 400 a (400 a + 200) × 2
                                             = 576 + 1000 a a × 400 a 400 a × 2200 × 2
                                             = 576 + 1000 a a × 400 a 800 a 400
                                             = 176 + 200 a a × 400 a
    The equation is transformed into :
     176 + 200 a a × 400 a = 200

    After the equation is converted into a general formula, it is converted into:
    ( 5a - 1 )( 10a - 3 )=0
    From
        5a - 1 = 0
        10a - 3 = 0

    it is concluded that::
        a1=
1
5
        a2=
3
10
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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