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    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 20 = 4.32(1+j)+4.5159*(1+j)*(1+j)+5.04*(1+j)*(1+j)*(1+j)+5.652*(1+j)*(1+j)*(1+j)*(1+j)+6.336*(1+j)*(1+j)*(1+j)*(1+j)*(1+j) .
    Question type: Equation
    Solution:Original question:
     20 =
108
25
(1 + j ) +
45159
10000
(1 + j )(1 + j ) +
126
25
(1 + j )(1 + j )(1 + j ) +
1413
250
(1 + j )(1 + j )
    Remove the bracket on the right of the equation:
     Right side of the equation =
108
25
× 1 +
108
25
j +
45159
10000
(1 + j )(1 + j ) +
126
25
(1 + j )(1 + j )(1 + j ) +
1413
250
                                               =
108
25
+
108
25
j +
45159
10000
(1 + j )(1 + j ) +
126
25
(1 + j )(1 + j )(1 + j ) +
1413
250
(1 + j )
                                               =
108
25
+
108
25
j +
45159
10000
× 1(1 + j ) +
45159
10000
j (1 + j ) +
126
25
(1 + j )(1 + j )
                                               =
108
25
+
108
25
j +
45159
10000
(1 + j ) +
45159
10000
j (1 + j ) +
126
25
(1 + j )(1 + j )(1 + j )
                                               =
108
25
+
108
25
j +
45159
10000
× 1 +
45159
10000
j +
45159
10000
j (1 + j ) +
126
25
(1 + j )
                                               =
108
25
+
108
25
j +
45159
10000
+
45159
10000
j +
45159
10000
j (1 + j ) +
126
25
(1 + j )(1 + j )
                                               =
88359
10000
+
88359
10000
j +
45159
10000
j (1 + j ) +
126
25
(1 + j )(1 + j )(1 + j ) +
1413
250
(1 + j )
                                               =
88359
10000
+
88359
10000
j +
45159
10000
j × 1 +
45159
10000
j j +
126
25
(1 + j )(1 + j )
                                               =
88359
10000
+
88359
10000
j +
45159
10000
j +
45159
10000
j j +
126
25
(1 + j )(1 + j )(1 + j )
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
(1 + j )(1 + j )(1 + j ) +
1413
250
(1 + j )
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
× 1(1 + j )(1 + j ) +
126
25
j
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
(1 + j )(1 + j ) +
126
25
j (1 + j )
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
× 1(1 + j ) +
126
25
j (1 + j )
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
(1 + j ) +
126
25
j (1 + j ) +
126
25
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
× 1 +
126
25
j +
126
25
j
                                               =
88359
10000
+
66759
5000
j +
45159
10000
j j +
126
25
+
126
25
j +
126
25
j (1 + j )
                                               =
138759
10000
+
91959
5000
j +
45159
10000
j j +
126
25
j (1 + j ) +
126
25
j (1 + j )
                                               =
138759
10000
+
91959
5000
j +
45159
10000
j j +
126
25
j × 1 +
126
25
j j
                                               =
138759
10000
+
91959
5000
j +
45159
10000
j j +
126
25
j +
126
25
j j +
126
25
                                               =
138759
10000
+
117159
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j (1 + j )
                                               =
138759
10000
+
117159
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j × 1
                                               =
138759
10000
+
117159
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j (1 + j )
                                               =
138759
10000
+
117159
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j × 1
                                               =
138759
10000
+
117159
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j +
126
25
                                               =
138759
10000
+
142359
5000
j +
45159
10000
j j +
126
25
j j +
126
25
j j

    
        j≈-0.079183 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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