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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (0.4*x+0.9)/0.5-(0.3+0.2*x)/0.3 = (x-5)/2 .
    Question type: Equation
    Solution:Original question:
     (
2
5
x +
9
10
) ÷
1
2
(
3
10
+
1
5
x ) ÷
3
10
= ( x 5) ÷ 2
    Remove the bracket on the left of the equation:
     Left side of the equation =
2
5
x × 2 +
9
10
× 2(
3
10
+
1
5
x ) ×
10
3
                                             =
4
5
x +
9
5
(
3
10
+
1
5
x ) ×
10
3
                                             =
4
5
x +
9
5
3
10
×
10
3
1
5
x ×
10
3
                                             =
4
5
x +
9
5
1
2
3
x
                                             =
2
15
x +
4
5
    The equation is transformed into :
     
2
15
x +
4
5
= ( x 5) ÷ 2
    Remove the bracket on the right of the equation:
     Right side of the equation = x ×
1
2
5 ×
1
2
                                               = x ×
1
2
5
2
    The equation is transformed into :
     
2
15
x +
4
5
=
1
2
x
5
2

    Transposition :
     
2
15
x
1
2
x = -
5
2
4
5

    Combine the items on the left of the equation:
      -
11
30
x = -
5
2
4
5

    Combine the items on the right of the equation:
      -
11
30
x = -
33
10

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     
33
10
=
11
30
x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
11
30
x =
33
10

    The coefficient of the unknown number is reduced to 1 :
      x =
33
10
÷
11
30
        =
33
10
×
30
11
        = 3 × 3

    We obtained :
      x = 9
    This is the solution of the equation.



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