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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 3080x2-{[3080/(1+12%)]+[3080/(1-12%)]} = x .
    Question type: Equation
    Solution:Original question:
     3080 x × 2 − ((3080 ÷ (1 +
12
100
)) + (3080 ÷ (1 −
12
100
))) = x
    Remove a bracket on the left of the equation:：
     3080 x × 2 − (3080 ÷ (1 +
12
100
)) − (3080 ÷ (1 −
12
100
)) = x
    The equation is reduced to :
     6160 x − (3080 ÷ (1 +
12
100
)) − (3080 ÷ (1 −
12
100
)) = x
    Remove a bracket on the left of the equation:
     6160 x − 3080 ÷ (1 +
12
100
) − (3080 ÷ (1 −
12
100
)) = x
     Multiply both sides of the equation by:(1 +
12
100
)
     6160 x (1 +
12
100
) − 3080 − (3080 ÷ (1 −
12
100
))(1 +
12
100
) = x (1 +
12
100
)
    Remove a bracket on the left of the equation:
     6160 x × 1 + 6160 x ×
12
100
 − 3080 − (3080 ÷ (1 −
12
100
))(1 +
12
100
) = x (1 +
12
100
)
    Remove a bracket on the right of the equation:：
     6160 x × 1 + 6160 x ×
12
100
 − 3080 − (3080 ÷ (1 −
12
100
))(1 +
12
100
) = x × 1 + x ×
12
100
    The equation is reduced to :
     6160 x +
3696
5
 x − 3080 − (3080 ÷ (1 −
12
100
))(1 +
12
100
) = x × 1 + x ×
12
100
    The equation is reduced to :
     
34496
5
 x − 3080 − (3080 ÷ (1 −
12
100
))(1 +
12
100
) =
28
25
 x
    Remove a bracket on the left of the equation:
     
34496
5
 x − 3080 − 3080 ÷ (1 −
12
100
) × (1 +
12
100
) =
28
25
 x
     Multiply both sides of the equation by:(1 −
12
100
)
     
34496
5
 x (1 −
12
100
) − 3080(1 −
12
100
) − 3080(1 +
12
100
) =
28
25
 x (1 −
12
100
)
    Remove a bracket on the left of the equation:
     
34496
5
 x × 1 −
34496
5
 x ×
12
100
 − 3080(1 −
12
100
) − 3080(1 +
12
100
) =
28
25
 x (1 −
12
100
)
    Remove a bracket on the right of the equation:：
     
34496
5
 x × 1 −
34496
5
 x ×
12
100
 − 3080(1 −
12
100
) − 3080(1 +
12
100
) =
28
25
 x × 1 −
28
25
 x ×
12
100
    The equation is reduced to :
     
34496
5
 x −
103488
125
 x − 3080(1 −
12
100
) − 3080(1 +
12
100
) =
28
25
 x −
84
625
 x
    The equation is reduced to :
     
758912
125
 x − 3080(1 −
12
100
) − 3080(1 +
12
100
) =
616
625
 x
    Remove a bracket on the left of the equation:
     
758912
125
 x − 3080 × 1 + 3080 ×
12
100
 − 3080(1 +
12
100
) =
616
625
 x
    The equation is reduced to :
     
758912
125
 x − 3080 +
1848
5
 − 3080(1 +
12
100
) =
616
625
 x
    The equation is reduced to :
     
758912
125
 x −
13552
5
 − 3080(1 +
12
100
) =
616
625
 x
    Remove a bracket on the left of the equation:
     
758912
125
 x −
13552
5
 − 3080 × 1 − 3080 ×
12
100
 =
616
625
 x
    The equation is reduced to :
     
758912
125
 x −
13552
5
 − 3080 −
1848
5
 =
616
625
 x
    The equation is reduced to :
     
758912
125
 x − 6160 =
616
625
 x

    Transposition :
     
758912
125
 x −
616
625
 x = 6160

    Combine the items on the left of the equation:
     
3793944
625
 x = 6160

    The coefficient of the unknown number is reduced to 1 :
      x = 6160 ÷
3793944
625
        = 6160 ×
625
3793944
        = 110 ×
625
67749

    We obtained :
      x =
68750
67749
    This is the solution of the equation.

    By reducing fraction, we can get:
      x =
6250
6159

    Convert the result to decimal form :
      x = 1.014775



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