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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (5.67x+100+5.67)*(1.5x+100)/(5.67x+100)/(1.5x+100+1.5) = (20000/49+(x+1)*x)/(20000/49+x*x) .
    Question type: Equation
    Solution:Original question:
     (
567
100
x + 100 +
567
100
)(
3
2
x + 100) ÷ (
567
100
x + 100) ÷ (
3
2
x + 100 +
3
2
) = (20000 ÷ 49 + ( x + 1) x ) ÷ (20000 ÷ 49 + x x )
     Multiply both sides of the equation by:(
567
100
x + 100) ,  (20000 ÷ 49 + x x )
     (
567
100
x + 100 +
567
100
)(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) = (20000 ÷ 49 + ( x + 1) x )(
567
100
x + 100)
    Remove a bracket on the left of the equation::
     
567
100
x (
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) + 100(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) +
567
100
(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) = (20000 ÷ 49 + ( x + 1) x )(
567
100
x + 100)
    Remove a bracket on the right of the equation::
     
567
100
x (
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) + 100(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) +
567
100
(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) = 20000 ÷ 49 × (
567
100
x + 100) + ( x + 1) x (
567
100
x + 100)
    The equation is reduced to :
     
567
100
x (
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) + 100(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) × (20000 ÷ 49 + x x ) +
567
100
(
3
2
x + 100) ÷ (
3
2
x + 100 +
3
2
) =
20000
49
(
567
100
x + 100) + ( x + 1) x (
567
100
x + 100)
     Multiply both sides of the equation by:(
3
2
x + 100 +
3
2
)
     
567
100
x (
3
2
x + 100)(20000 ÷ 49 + x x ) + 100(
3
2
x + 100)(20000 ÷ 49 + x x ) +
567
100
(
3
2
x + 100)(20000 ÷ 49 + x x ) =
20000
49
(
567
100
x + 100)(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the left of the equation:
     
567
100
x ×
3
2
x (20000 ÷ 49 + x x ) +
567
100
x × 100(20000 ÷ 49 + x x ) + 100(
3
2
x + 100)(20000 ÷ 49 + x x ) =
20000
49
(
567
100
x + 100)(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the right of the equation::
     
567
100
x ×
3
2
x (20000 ÷ 49 + x x ) +
567
100
x × 100(20000 ÷ 49 + x x ) + 100(
3
2
x + 100)(20000 ÷ 49 + x x ) =
20000
49
×
567
100
x (
3
2
x + 100 +
3
2
) +
20000
49
× 100(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    The equation is reduced to :
     
1701
200
x x (20000 ÷ 49 + x x ) + 567 x (20000 ÷ 49 + x x ) + 100(
3
2
x + 100)(20000 ÷ 49 + x x ) +
567
100
(
3
2
x + 100) =
16200
7
x (
3
2
x + 100 +
3
2
) +
2000000
49
(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the left of the equation:
     
1701
200
x x × 20000 ÷ 49 +
1701
200
x x x x + 567 x =
16200
7
x (
3
2
x + 100 +
3
2
) +
2000000
49
(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the right of the equation::
     
1701
200
x x × 20000 ÷ 49 +
1701
200
x x x x + 567 x =
16200
7
x ×
3
2
x +
16200
7
x × 100 +
16200
7
x ×
3
2
+
2000000
49
(
3
2
x + 100 +
3
2
)
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x + 567 x (20000 ÷ 49 + x x ) + 100 =
24300
7
x x +
1620000
7
x +
24300
7
x +
2000000
49
(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x + 567 x (20000 ÷ 49 + x x ) + 100 =
24300
7
x x + 234900 x +
2000000
49
(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the left of the equation:
     
24300
7
x x +
1701
200
x x x x + 567 x × 20000 ÷ 49 =
24300
7
x x + 234900 x +
2000000
49
(
3
2
x + 100 +
3
2
) + ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the right of the equation::
     
24300
7
x x +
1701
200
x x x x + 567 x × 20000 ÷ 49 =
24300
7
x x + 234900 x +
2000000
49
×
3
2
x +
2000000
49
× 100 +
2000000
49
×
3
2
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x + 234900 x +
3000000
49
x +
200000000
49
+
3000000
49
+ ( x + 1) x (
567
100
x + 100)
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the left of the equation:
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ ( x + 1) x (
567
100
x + 100)(
3
2
x + 100 +
3
2
)
    Remove a bracket on the right of the equation::
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ x x (
567
100
x + 100)(
3
2
x + 100 +
3
2
) + 1 x
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ x x (
567
100
x + 100)(
3
2
x + 100 +
3
2
) + 1 x
    Remove a bracket on the left of the equation:
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ x x (
567
100
x + 100)(
3
2
x + 100 +
3
2
) + 1 x
    Remove a bracket on the right of the equation::
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ x x ×
567
100
x (
3
2
x + 100 +
3
2
) + x
    The equation is reduced to :
     
24300
7
x x +
1701
200
x x x x +
1620000
7
x + 567 x =
24300
7
x x +
14510100
49
x +
29000000
7
+ x x ×
567
100
x (
3
2
x + 100 +
3
2
) + x

    After the equation is converted into a general formula, there is a common factor:
    ( √200000x - √26392957 )
    From
        √200000x - √26392957 = 0

    it is concluded that::
        x1=
√26392957
√200000

    Solutions that cannot be obtained by factorization:
        x2≈-17.636684 , keep 6 decimal places
    
    There are 2 solution(s).


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