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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 16×8a+(300-20-8a)×[16×(1-a%)] = 4160 .
    Question type: Equation
    Solution:Original question:
     16 × 8 a + (300208 a )(16(1 a )) = 4160
     Left side of the equation = 128 a + (300208 a )(16(1 a ))
    The equation is transformed into :
     128 a + (300208 a )(16(1 a )) = 4160
    Remove the bracket on the left of the equation:
     Left side of the equation = 128 a + 300(16(1 a ))20(16(1 a ))8 a (16(1 a ))
                                             = 128 a + 300 × 16(1 a )20(16(1 a ))8 a (16(1 a ))
                                             = 128 a + 4800(1 a )20(16(1 a ))8 a (16(1 a ))
                                             = 128 a + 4800 × 14800 a 20(16(1 a ))8 a (16(1 a ))
                                             = 128 a + 48004800 a 20(16(1 a ))8 a (16(1 a ))
                                             = - 4672 a + 480020(16(1 a ))8 a (16(1 a ))
                                             = - 4672 a + 480020 × 16(1 a )8 a (16(1 a ))
                                             = - 4672 a + 4800320(1 a )8 a (16(1 a ))
                                             = - 4672 a + 4800320 × 1 + 320 a 8 a (16(1 a ))
                                             = - 4672 a + 4800320 + 320 a 8 a (16(1 a ))
                                             = - 4352 a + 44808 a (16(1 a ))
                                             = - 4352 a + 44808 a × 16(1 a )
                                             = - 4352 a + 4480128 a (1 a )
                                             = - 4352 a + 4480128 a × 1 + 128 a a
                                             = - 4352 a + 4480128 a + 128 a a
                                             = - 4480 a + 4480 + 128 a a
    The equation is transformed into :
      - 4480 a + 4480 + 128 a a = 4160

    After the equation is converted into a general formula, it is converted into:
    ( a - 10 )( a - 25 )=0
    From
        a - 10 = 0
        a - 25 = 0

    it is concluded that::
        a1=10
        a2=25
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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