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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (z-0.414*0.082)*(z+2.414*0.082)*(1.082-z)/0.082/9.46 = 0 .
    Question type: Equation
    Solution:Original question:
     ( z
207
500
×
41
500
)( z +
1207
500
×
41
500
)(
541
500
z ) ÷
41
500
÷
473
50
= 0
     Left side of the equation = ( z
207
500
×
41
500
)( z +
1207
500
×
41
500
)(
541
500
z ) ×
25000
19393
    The equation is transformed into :
     ( z
207
500
×
41
500
)( z +
1207
500
×
41
500
)(
541
500
z ) ×
25000
19393
= 0
    Remove the bracket on the left of the equation:
     Left side of the equation = z ( z +
1207
500
×
41
500
)(
541
500
z ) ×
25000
19393
207
500
×
41
500
( z +
1207
500
×
41
500
)(
541
500
z ) ×
25000
19393
                                             = z ( z +
1207
500
×
41
500
)(
541
500
z ) ×
25000
19393
207
4730
( z +
1207
500
×
41
500
)(
541
500
z )
                                             = z z (
541
500
z ) ×
25000
19393
+ z ×
1207
500
×
41
500
(
541
500
z ) ×
25000
19393
207
4730
( z +
1207
500
×
41
500
)(
541
500
z )
                                             = z z (
541
500
z ) ×
25000
19393
+ z ×
1207
4730
(
541
500
z )
207
4730
( z +
1207
500
×
41
500
)(
541
500
z )
                                             = z z ×
541
500
×
25000
19393
z z z ×
25000
19393
+ z ×
1207
4730
(
541
500
z )
207
4730
                                             = z z ×
27050
19393
z z z ×
25000
19393
+ z ×
1207
4730
(
541
500
z )
207
4730
( z +
1207
500
×
41
500
)
                                             = z z ×
27050
19393
z z z ×
25000
19393
+ z ×
1207
4730
×
541
500
z ×
1207
4730
                                             = z z ×
27050
19393
z z z ×
25000
19393
+ z ×
652987
2365000
z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
652987
2365000
z z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
652987
2365000
z z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
652987
2365000
z z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
652987
2365000
z z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
541
2365
z z ×
1207
4730
z
                                             = z z ×
27050
19393
z z z ×
25000
19393
+
541
2365
z z ×
1207
4730
z

    After the equation is converted into a general formula, it is converted into:
    ( 250000z + 49487 )( 250000z - 8487 )( 500z - 541 )=0
    From
        250000z + 49487 = 0
        250000z - 8487 = 0
        500z - 541 = 0

    it is concluded that::
        z1=-
49487
250000
        z2=
8487
250000
        z3=
541
500
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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