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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (6-0.1*m)*(140+4*m)+12*(120-0.5*m) = 2280 .
    Question type: Equation
    Solution:Original question:
     (6
1
10
m )(140 + 4 m ) + 12(120
1
2
m ) = 2280
    Remove the bracket on the left of the equation:
     Left side of the equation = 6(140 + 4 m )
1
10
m (140 + 4 m ) + 12(120
1
2
m )
                                             = 6 × 140 + 6 × 4 m
1
10
m (140 + 4 m ) + 12(120
1
2
m )
                                             = 840 + 24 m
1
10
m (140 + 4 m ) + 12(120
1
2
m )
                                             = 840 + 24 m
1
10
m × 140
1
10
m × 4 m + 12(120
1
2
m )
                                             = 840 + 24 m 14 m
2
5
m m + 12(120
1
2
m )
                                             = 840 + 10 m
2
5
m m + 12(120
1
2
m )
                                             = 840 + 10 m
2
5
m m + 12 × 12012 ×
1
2
m
                                             = 840 + 10 m
2
5
m m + 14406 m
                                             = 2280 + 4 m
2
5
m m
    The equation is transformed into :
     2280 + 4 m
2
5
m m = 2280

    After the equation is converted into a general formula, it is converted into:
    ( m +0 )( m - 10 )=0
    From
        m + 0 = 0
        m - 10 = 0

    it is concluded that::
        m1=0
        m2=10
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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