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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 150(30000−600y)+110(20000−400y)+(190−y)(20000+600y+400y) = 10820000 .
    Question type: Equation
    Solution:Original question:
     150(30000600 y ) + 110(20000400 y ) + (190 y )(20000 + 600 y + 400 y ) = 10820000
    Remove the bracket on the left of the equation:
     Left side of the equation = 150 × 30000150 × 600 y + 110(20000400 y ) + (190 y )(20000 + 600 y + 400 y )
                                             = 450000090000 y + 110(20000400 y ) + (190 y )(20000 + 600 y + 400 y )
                                             = 450000090000 y + 110 × 20000110 × 400 y + (190 y )(20000 + 600 y + 400 y )
                                             = 450000090000 y + 220000044000 y + (190 y )(20000 + 600 y + 400 y )
                                             = 6700000134000 y + (190 y )(20000 + 600 y + 400 y )
                                             = 6700000134000 y + 190(20000 + 600 y + 400 y ) y (20000 + 600 y + 400 y )
                                             = 6700000134000 y + 190 × 20000 + 190 × 600 y + 190 × 400 y y
                                             = 6700000134000 y + 3800000 + 114000 y + 76000 y y (20000 + 600 y + 400 y )
                                             = 10500000 + 56000 y y (20000 + 600 y + 400 y )
                                             = 10500000 + 56000 y y × 20000 y × 600 y y × 400 y
                                             = 10500000 + 36000 y y × 600 y y × 400 y
    The equation is transformed into :
     10500000 + 36000 y y × 600 y y × 400 y = 10820000

    After the equation is converted into a general formula, it is converted into:
    ( y - 16 )( y - 20 )=0
    From
        y - 16 = 0
        y - 20 = 0

    it is concluded that::
        y1=16
        y2=20
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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