Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/(x+0.72)+1/(1.08-x) = 1/x+1/(1.8-x) .
    Question type: Equation
    Solution:Original question:
     1 ÷ ( x +
18
25
) + 1 ÷ (
27
25
x ) = 1 ÷ x + 1 ÷ (
9
5
x )
     Multiply both sides of the equation by:( x +
18
25
) ,   x
     1 x + 1 ÷ (
27
25
x ) × ( x +
18
25
) x = 1( x +
18
25
) + 1 ÷ (
9
5
x ) × ( x +
18
25
) x
    Remove a bracket on the left of the equation::
     1 x + 1 ÷ (
27
25
x ) × x x + 1 ÷ (
27
25
x ) ×
18
25
x = 1( x +
18
25
) + 1 ÷ (
9
5
x ) × ( x +
18
25
) x
    Remove a bracket on the right of the equation::
     1 x + 1 ÷ (
27
25
x ) × x x + 1 ÷ (
27
25
x ) ×
18
25
x = 1 x + 1 ×
18
25
+ 1 ÷ (
9
5
x ) × ( x +
18
25
) x
    The equation is reduced to :
     1 x + 1 ÷ (
27
25
x ) × x x +
18
25
÷ (
27
25
x ) × x = 1 x +
18
25
+ 1 ÷ (
9
5
x ) × ( x +
18
25
) x
     Multiply both sides of the equation by:(
27
25
x ) ,  (
9
5
x )
     1 x (
27
25
x )(
9
5
x ) + 1 x x (
9
5
x ) +
18
25
x (
9
5
x ) = 1 x (
27
25
x )(
9
5
x ) +
18
25
(
27
25
x )(
9
5
x ) + 1( x +
18
25
) x (
27
25
x )
    Remove a bracket on the left of the equation:
     1 x ×
27
25
(
9
5
x )1 x x (
9
5
x ) + 1 x x (
9
5
x ) = 1 x (
27
25
x )(
9
5
x ) +
18
25
(
27
25
x )(
9
5
x ) + 1( x +
18
25
) x (
27
25
x )
    Remove a bracket on the right of the equation::
     1 x ×
27
25
(
9
5
x )1 x x (
9
5
x ) + 1 x x (
9
5
x ) = 1 x ×
27
25
(
9
5
x )1 x x (
9
5
x ) +
18
25
(
27
25
x )(
9
5
x ) + 1
    The equation is reduced to :
     
27
25
x (
9
5
x )1 x x (
9
5
x ) + 1 x x (
9
5
x ) +
18
25
=
27
25
x (
9
5
x )1 x x (
9
5
x ) +
18
25
(
27
25
x )(
9
5
x ) + 1( x +
18
25
)
    Remove a bracket on the left of the equation:
     
27
25
x ×
9
5
27
25
x x 1 x x (
9
5
x ) + 1 x =
27
25
x (
9
5
x )1 x x (
9
5
x ) +
18
25
(
27
25
x )(
9
5
x ) + 1( x +
18
25
)
    Remove a bracket on the right of the equation::
     
27
25
x ×
9
5
27
25
x x 1 x x (
9
5
x ) + 1 x =
27
25
x ×
9
5
27
25
x x 1 x x (
9
5
x ) +
18
25
(
27
25
x )
    The equation is reduced to :
     
243
125
x
27
25
x x 1 x x (
9
5
x ) + 1 x x =
243
125
x
27
25
x x 1 x x (
9
5
x ) +
18
25
(
27
25
x )(
9
5
x )
    Remove a bracket on the left of the equation:
     
243
125
x
27
25
x x 1 x x ×
9
5
+ 1 x x =
243
125
x
27
25
x x 1 x x (
9
5
x ) +
18
25
(
27
25
x )(
9
5
x )
    Remove a bracket on the right of the equation::
     
243
125
x
27
25
x x 1 x x ×
9
5
+ 1 x x =
243
125
x
27
25
x x 1 x x ×
9
5
+ 1 x x
    The equation is reduced to :
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    Remove a bracket on the left of the equation:
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    Remove a bracket on the right of the equation::
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    The equation is reduced to :
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    Remove a bracket on the left of the equation:
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    Remove a bracket on the right of the equation::
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    The equation is reduced to :
     
243
125
x
27
25
x x
9
5
x x + 1 x x x =
243
125
x
27
25
x x
9
5
x x + 1 x x x
    The equation is reduced to :
     
81
25
x
27
25
x x
9
5
x x + 1 x x x =
729
625
x
27
25
x x
9
5
x x + 1 x x x

    
        x1=
27
50
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。