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On line Solution of Monovariate Equation：
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 31000 = x−[x/(1+3%)×3%×(1+7%)−{[x/(1+3%)]×(1−20%)×30%−2000} ) .
    Question type: Equation
    Solution:Original question:
     31000 = x − ( x ÷ (1 +
3
100
) ×
3
100
(1 +
7
100
) − (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000))
    Remove a bracket on the right of the equation:：
     31000 = x − x ÷ (1 +
3
100
) ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)
     Multiply both sides of the equation by:(1 +
3
100
)
     31000(1 +
3
100
) = x (1 +
3
100
) − x ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    Remove a bracket on the left of the equation:
     31000 × 1 + 31000 ×
3
100
 = x (1 +
3
100
) − x ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    Remove a bracket on the right of the equation:：
     31000 × 1 + 31000 ×
3
100
 = x × 1 + x ×
3
100
 − x ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    The equation is reduced to :
     31000 + 930 = x × 1 + x ×
3
100
 − x ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    The equation is reduced to :
     31930 =
103
100
 x − x ×
3
100
(1 +
7
100
) + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    Remove a bracket on the right of the equation:：
     31930 =
103
100
 x − x ×
3
100
 × 1 − x ×
3
100
 ×
7
100
 + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    The equation is reduced to :
     31930 =
103
100
 x − x ×
3
100
 − x ×
21
10000
 + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    The equation is reduced to :
     31930 =
9979
10000
 x + (( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
 − 2000)(1 +
3
100
)
    Remove a bracket on the right of the equation:：
     31930 =
9979
10000
 x + ( x ÷ (1 +
3
100
))(1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)
    Remove a bracket on the right of the equation:：
     31930 =
9979
10000
 x + x ÷ (1 +
3
100
) × (1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)
     Multiply both sides of the equation by:(1 +
3
100
)
     31930(1 +
3
100
) =
9979
10000
 x (1 +
3
100
) + x (1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)(1 +
3
100
)
    Remove a bracket on the left of the equation:
     31930 × 1 + 31930 ×
3
100
 =
9979
10000
 x (1 +
3
100
) + x (1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)(1 +
3
100
)
    Remove a bracket on the right of the equation:：
     31930 × 1 + 31930 ×
3
100
 =
9979
10000
 x × 1 +
9979
10000
 x ×
3
100
 + x (1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)
    The equation is reduced to :
     31930 +
9579
10
 =
9979
10000
 x +
29937
1000000
 x + x (1 −
20
100
) ×
30
100
(1 +
3
100
) − 2000(1 +
3
100
)(1 +
3
100
)

    
        x=31000    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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