Overview: 5 questions will be solved this time.Among them
           ☆3 equations
           ☆1 arithmetic calculations
           ☆1 integer calculations

[ 1/5 Equation]
    Work: Find the solution of equation [3+4i]/[1-2i]-[-1+4] = 0 .
    Question type: Equation
    Solution:Original question:

(

3

+

4

i

)

÷

(

1

−

2

i

)

−

(

-

1

+

4

)

=

0

Multiply both sides of the equation by:

(

1

−

2

i

)

(

3

+

4

i

)

−

(

-

1

+

4

)

(

1

−

2

i

)

=

0

    Remove a bracket on the left of the equation:：

3

+

4

i

−

(

-

1

+

4

)

(

1

−

2

i

)

=

0

    Remove a bracket on the left of the equation:

3

+

4

i

+

1

(

1

−

2

i

)

−

4

(

1

−

2

i

)

=

0

    Remove a bracket on the left of the equation:

3

+

4

i

+

1

×

1

−

1

×

2

i

−

4

(

1

−

2

i

)

=

0

    The equation is reduced to :

3

+

4

i

+

1

−

2

i

−

4

(

1

−

2

i

)

=

0

    The equation is reduced to :

4

+

2

i

−

4

(

1

−

2

i

)

=

0

    Remove a bracket on the left of the equation:

4

+

2

i

−

4

×

1

+

4

×

2

i

=

0

    The equation is reduced to :

4

+

2

i

−

4

+

8

i

=

0

    The equation is reduced to :

0

+

10

i

=

0

    The coefficient of the unknown number is reduced to 1 :

i

=

0

÷

10

=

0

×

1 10

    We obtained :

i

=

0

    This is the solution of the equation.

[2/% Digital analysis]
    Assignment: Convert 200/40 to decimal.
    Question type: Convert fraction to decimal
    Solution:
    First reduce fraction:
        The numerator and denominator of the fraction 200/40 are reduced to the simplest fraction by the common divisor 2,2,2,5,
        is: 5/1
        5/1=5
    *Note: Can be converted to integer.
[3/5 Formula]
    Work: Calculate the value of equation 160+40*20 .
    Question type: Mathematical calculation
    Solution:
          160+40*20
        =160+800
        =960
    Answer:160+40*20=960
[ 4/5 Equation]
    Work: Find the solution of equation [1+i]*[2+4i]+[-3+i] = 0 .
    Question type: Equation
    Solution:Original question:

(

1

+

i

)

(

2

+

4

i

)

+

(

-

3

+

i

)

=

0

    Remove the bracket on the left of the equation:

Left side of the equation =

1

(

2

+

4

i

)

+

i

(

2

+

4

i

)

+

(

-

3

+

i

)

=

1

×

2

+

1

×

4

i

+

i

(

2

+

4

i

)

+

(

-

3

+

i

)

=

2

+

4

i

+

i

(

2

+

4

i

)

+

(

-

3

+

i

)

=

2

+

4

i

+

i

×

2

+

i

×

4

i

+

(

-

3

+

i

)

=

2

+

6

i

+

i

×

4

i

+

(

-

3

+

i

)

=

2

+

6

i

+

i

×

4

i

−

3

+

i

=

-

1

+

7

i

+

i

×

4

i

    The equation is transformed into :

-

1

+

7

i

+

i

×

4

i

=

0

    The solution of the equation:
        i₁≈-1.882782 , keep 6 decimal places
        i₂≈0.132782 , keep 6 decimal places    
    There are 2 solution(s).

解程的详细方法请参阅：《方程的解法》
[ 5/5 Equation]
    Work: Find the solution of equation a+2a = 0 .
    Question type: Equation
    Solution:Original question:

a

+

2

a

=

0

Left side of the equation =

3

a

    The equation is transformed into :

3

a

=

0

    The coefficient of the unknown number is reduced to 1 :

a

=

0

÷

3

=

0

×

1 3

    We obtained :

a

=

0

    This is the solution of the equation.

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