Overview: 7 questions will be solved this time.Among them
☆3 inequalities
☆2 equations
☆2 arithmetic calculations
[ 1/7 Equation]
Work: Find the solution of equation x^2+x = 1 .
Question type: Equation
Solution:
The solution of the equation:
x1≈-1.618034 , keep 6 decimal places
x2≈0.618034 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅:《方程的解法》[ 2/7Inequality]
Assignment:Find the solution set of inequality x^2 <-1 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
x ^ 2 < -1 (1)
From inequality(1):
The solution set is empty, that is, within the range of real numbers, the inequality will never be established!
The final solution set is :
The solution set is empty,that is, the inequality will never be estatlished within the real number range.
[ 3/7Inequality]
Assignment:Find the solution set of inequality x^4 ≥-4 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
x ^ 4 ≥ -4 (1)
From inequality(1):
x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
The final solution set is :
x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established![4/7 Formula]
Work: Calculate the value of equation √((-2)^4) .
Question type: Mathematical calculation
Solution:
√((-2)^4)
=√((-2)^4)
=√16
=4 Answer:√((-2)^4)=4[5/7 Formula]
Work: Calculate the value of equation (√5-1)/2 .
Question type: Mathematical calculation
Solution:
(√5-1)/2
=1.236068/2
=0.618034 Answer:(√5-1)/2=0.618034[ 6/7Inequality]
Assignment:Find the solution set of inequality x+1 >0 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
x + 1 >0 (1)
From inequality(1):
x > -1
The final solution set is :
x > -1[ 7/7 Equation]
Work: Find the solution of equation x/3 = 3 .
Question type: Equation
Solution:Original question:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
>>注:本次最多计算 7 道题。
Your problem has not been solved here? Please go to the Hot Problems section!