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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (1/2020)(y+1)+3 = 2(y+1)+(18177/2020) .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
Remove the bracket on the right of the equation:
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
By reducing fraction, we can get:
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (1/2020)(y+1)+3 = 2(y+1)+(18177/2020) .
Question type: Equation
Solution:Original question:
| ( | 1 | ÷ | 2020 | ) | ( | y | + | 1 | ) | + | 3 | = | 2 | ( | y | + | 1 | ) | + | ( | 18177 | ÷ | 2020 | ) |
| Left side of the equation = | 1 | ÷ | 2020 | × | ( | y | + | 1 | ) | + | 3 |
| = | 1 2020 | ( | y | + | 1 | ) | + | 3 |
| = | 1 2020 | y | + | 1 2020 | × | 1 | + | 3 |
| = | 1 2020 | y | + | 1 2020 | + | 3 |
| = | 1 2020 | y | + | 6061 2020 |
1 2020 | y | + | 6061 2020 | = | 2 | ( | y | + | 1 | ) | + | ( | 18177 | ÷ | 2020 | ) |
| Right side of the equation = | 2 | y | + | 2 | × | 1 | + | ( | 18177 | ÷ | 2020 | ) |
| = | 2 | y | + | 2 | + | ( | 18177 | ÷ | 2020 | ) |
| = | 2 | y | + | 2 | + | 18177 | ÷ | 2020 |
| = | 2 | y | + | 2 | + | 18177 2020 |
| = | 2 | y | + | 22217 2020 |
1 2020 | y | + | 6061 2020 | = | 2 | y | + | 22217 2020 |
Transposition :
1 2020 | y | − | 2 | y | = | 22217 2020 | − | 6061 2020 |
Combine the items on the left of the equation:
| - | 4039 2020 | y | = | 22217 2020 | − | 6061 2020 |
Combine the items on the right of the equation:
| - | 4039 2020 | y | = | 4039 505 |
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
| - | 4039 505 | = | 4039 2020 | y |
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
4039 2020 | y | = | - | 4039 505 |
The coefficient of the unknown number is reduced to 1 :
| y | = | - | 4039 505 | ÷ | 4039 2020 |
| = | - | 4039 505 | × | 2020 4039 |
| = | - | 577 101 | × | 404 577 |
We obtained :
| y | = | - | 233108 58277 |
By reducing fraction, we can get:
| y | = | - | 4 |