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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation -26.67(2*80/3(1-x)+3)+26.67(40x+40/3(1-x)+4)+20(30x+10(1-x)+2)-20(60(1-x)+1)+26.67(80x+80/3(1-x)+1)+20(60x+20(1-x)+1) = 0 .
    Question type: Equation
    Solution:Original question:
      -
2667
100
(2 × 80 ÷ 3 × (1 x ) + 3) +
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = -
2667
100
× 2 × 80 ÷ 3 × (1 x )
2667
100
× 3 +
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20
                                             = -
7112
5
(1 x )
8001
100
+
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20
                                             = -
7112
5
× 1 +
7112
5
x
8001
100
+
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
                                             = -
7112
5
+
7112
5
x
8001
100
+
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1)
                                             = -
150241
100
+
7112
5
x +
2667
100
(40 x + 40 ÷ 3 × (1 x ) + 4) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20
                                             = -
150241
100
+
7112
5
x +
2667
100
× 40 x +
2667
100
× 40 ÷ 3 × (1 x ) +
2667
100
× 4
                                             = -
150241
100
+
7112
5
x +
5334
5
x +
1778
5
(1 x ) +
2667
25
+ 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1)
                                             = -
139573
100
+
12446
5
x +
1778
5
(1 x ) + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20
                                             = -
139573
100
+
12446
5
x +
1778
5
× 1
1778
5
x + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
                                             = -
139573
100
+
12446
5
x +
1778
5
1778
5
x + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1)
                                             = -
104013
100
+
10668
5
x + 20(30 x + 10(1 x ) + 2)20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
104013
100
+
10668
5
x + 20 × 30 x + 20 × 10(1 x ) + 20 × 220
                                             = -
104013
100
+
10668
5
x + 600 x + 200(1 x ) + 4020(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1)
                                             = -
100013
100
+
13668
5
x + 200(1 x )20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
100013
100
+
13668
5
x + 200 × 1200 x 20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20
                                             = -
100013
100
+
13668
5
x + 200200 x 20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
80013
100
+
12668
5
x 20(60(1 x ) + 1) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
80013
100
+
12668
5
x 20 × 60(1 x )20 × 1 +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
80013
100
+
12668
5
x 1200(1 x )20 +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
82013
100
+
12668
5
x 1200(1 x ) +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
82013
100
+
12668
5
x 1200 × 1 + 1200 x +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
82013
100
+
12668
5
x 1200 + 1200 x +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
202013
100
+
18668
5
x +
2667
100
(80 x + 80 ÷ 3 × (1 x ) + 1) + 20(60 x + 20(1 x ) + 1)
                                             = -
202013
100
+
18668
5
x +
2667
100
× 80 x +
2667
100
× 80 ÷ 3 × (1 x ) +
2667
100
× 1
                                             = -
202013
100
+
18668
5
x +
10668
5
x +
3556
5
(1 x ) +
2667
100
+ 20(60 x + 20(1 x ) + 1)

    
        x≈0.144772 , keep 6 decimal places
    
    There are 1 solution(s).


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