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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation X = 6*0.56+(1-0.5)(1+X)+0.5(1-0.5)(2+X)+0.52(1-0.5)(3+X)+0.53(1-0.5)(4+X)+0.54(1-0.5)(5+X)+0.55(1-0.5)(6+X) .
    Question type: Equation
    Solution:Original question:
      X = 6 ×
14
25
 + (1 −
1
2
)(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)
     Right side of the equation =
84
25
 + (1 −
1
2
)(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
    The equation is transformed into :
      X =
84
25
 + (1 −
1
2
)(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
    Remove the bracket on the right of the equation:
     Right side of the equation =
84
25
 + 1(1 + X ) −
1
2
(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
                                               =
84
25
 + 1 × 1 + 1 X −
1
2
(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)
                                               =
84
25
 + 1 + 1 X −
1
2
(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X )
                                               =
109
25
 + 1 X −
1
2
(1 + X ) +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
                                               =
109
25
 + 1 X −
1
2
 × 1 −
1
2
 X +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)
                                               =
109
25
 + 1 X −
1
2
 −
1
2
 X +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X )
                                               =
193
50
 +
1
2
 X +
1
2
(1 −
1
2
)(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
                                               =
193
50
 +
1
2
 X +
1
2
 × 1(2 + X ) −
1
2
 ×
1
2
(2 + X ) +
13
25
(1 −
1
2
)(3 + X )
                                               =
193
50
 +
1
2
 X +
1
2
(2 + X ) −
1
4
(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)
                                               =
193
50
 +
1
2
 X +
1
2
 × 2 +
1
2
 X −
1
4
(2 + X ) +
13
25
(1 −
1
2
)(3 + X )
                                               =
193
50
 +
1
2
 X + 1 +
1
2
 X −
1
4
(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
                                               =
243
50
 + 1 X −
1
4
(2 + X ) +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X ) +
27
50
                                               =
243
50
 + 1 X −
1
4
 × 2 −
1
4
 X +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)
                                               =
243
50
 + 1 X −
1
2
 −
1
4
 X +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
                                               =
109
25
 +
3
4
 X +
13
25
(1 −
1
2
)(3 + X ) +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)(5 + X )
                                               =
109
25
 +
3
4
 X +
13
25
 × 1(3 + X ) −
13
25
 ×
1
2
(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
                                               =
109
25
 +
3
4
 X +
13
25
(3 + X ) −
13
50
(3 + X ) +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)
                                               =
109
25
 +
3
4
 X +
13
25
 × 3 +
13
25
 X −
13
50
(3 + X ) +
53
100
(1 −
1
2
)(4 + X )
                                               =
109
25
 +
3
4
 X +
39
25
 +
13
25
 X −
13
50
(3 + X ) +
53
100
(1 −
1
2
)(4 + X ) +
27
50
                                               =
148
25
 +
127
100
 X −
13
50
(3 + X ) +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)(5 + X ) +
11
20
                                               =
148
25
 +
127
100
 X −
13
50
 × 3 −
13
50
 X +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)
                                               =
148
25
 +
127
100
 X −
39
50
 −
13
50
 X +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)(5 + X )
                                               =
257
50
 +
101
100
 X +
53
100
(1 −
1
2
)(4 + X ) +
27
50
(1 −
1
2
)(5 + X ) +
11
20
(1 −
1
2
)(6 + X )

    
        X≈-11.219512 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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