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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 6 questions will be solved this time.Among them
☆6 equations
[ 1/6 Equation]
Work: Find the solution of equation ４x×３＋４２ = ２９７－３x .
Question type: Equation
Solution:Original question:
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 2/6 Equation]
Work: Find the solution of equation ４x×３＋３０ = ２４６－４x×３ .
Question type: Equation
Solution:Original question:
The equation is transformed into :
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 3/6 Equation]
Work: Find the solution of equation ２x×６＋１９ = １９＋５x×２ .
Question type: Equation
Solution:Original question:
The equation is transformed into :
The equation is transformed into :
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 4/6 Equation]
Work: Find the solution of equation (x＋２．５)×５ = １４ .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
Transposition :
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
Convert the result to decimal form :
[ 5/6 Equation]
Work: Find the solution of equation ２x×３＋３x－３２ = １１２ .
Question type: Equation
Solution:Original question:
The equation is transformed into :
Transposition :
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 6/6 Equation]
Work: Find the solution of equation ４x×２＋４x－２５ = １１９ .
Question type: Equation
Solution:Original question:
The equation is transformed into :
Transposition :
Combine the items on the right of the equation:
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
☆6 equations
[ 1/6 Equation]
Work: Find the solution of equation ４x×３＋４２ = ２９７－３x .
Question type: Equation
Solution:Original question:
| 4 | x | × | 3 | + | 42 | = | 297 | − | 3 | x |
| Left side of the equation = | 12 | x | + | 42 |
| 12 | x | + | 42 | = | 297 | − | 3 | x |
Transposition :
| 12 | x | + | 3 | x | = | 297 | − | 42 |
Combine the items on the left of the equation:
| 15 | x | = | 297 | − | 42 |
Combine the items on the right of the equation:
| 15 | x | = | 255 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 255 | ÷ | 15 |
| = | 255 | × | 1 15 |
| = | 17 | × | 1 |
We obtained :
| x | = | 17 |
[ 2/6 Equation]
Work: Find the solution of equation ４x×３＋３０ = ２４６－４x×３ .
Question type: Equation
Solution:Original question:
| 4 | x | × | 3 | + | 30 | = | 246 | − | 4 | x | × | 3 |
| Left side of the equation = | 12 | x | + | 30 |
| 12 | x | + | 30 | = | 246 | − | 4 | x | × | 3 |
| Right side of the equation = | 246 | − | 12 | x |
| 12 | x | + | 30 | = | 246 | − | 12 | x |
Transposition :
| 12 | x | + | 12 | x | = | 246 | − | 30 |
Combine the items on the left of the equation:
| 24 | x | = | 246 | − | 30 |
Combine the items on the right of the equation:
| 24 | x | = | 216 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 216 | ÷ | 24 |
| = | 216 | × | 1 24 |
| = | 9 | × | 1 |
We obtained :
| x | = | 9 |
[ 3/6 Equation]
Work: Find the solution of equation ２x×６＋１９ = １９＋５x×２ .
Question type: Equation
Solution:Original question:
| 2 | x | × | 6 | + | 19 | = | 19 | + | 5 | x | × | 2 |
| Left side of the equation = | 12 | x | + | 19 |
| 12 | x | + | 19 | = | 19 | + | 5 | x | × | 2 |
| Right side of the equation = | 19 | + | 10 | x |
| 12 | x | + | 19 | = | 19 | + | 10 | x |
Transposition :
| 12 | x | − | 10 | x | = | 19 | − | 19 |
Combine the items on the left of the equation:
| 2 | x | = | 19 | − | 19 |
Combine the items on the right of the equation:
| 2 | x | = | 0 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 0 | ÷ | 2 |
| = | 0 | × | 1 2 |
We obtained :
| x | = | 0 |
[ 4/6 Equation]
Work: Find the solution of equation (x＋２．５)×５ = １４ .
Question type: Equation
Solution:Original question:
| ( | x | + | 5 2 | ) | × | 5 | = | 14 |
| Left side of the equation = | x | × | 5 | + | 5 2 | × | 5 |
| = | x | × | 5 | + | 25 2 |
| 5 | x | + | 25 2 | = | 14 |
Transposition :
| 5 | x | = | 14 | − | 25 2 |
Combine the items on the right of the equation:
| 5 | x | = | 3 2 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 3 2 | ÷ | 5 |
| = | 3 2 | × | 1 5 |
We obtained :
| x | = | 3 10 |
Convert the result to decimal form :
| x | = | 0.3 |
[ 5/6 Equation]
Work: Find the solution of equation ２x×３＋３x－３２ = １１２ .
Question type: Equation
Solution:Original question:
| 2 | x | × | 3 | + | 3 | x | − | 32 | = | 112 |
| Left side of the equation = | 6 | x | + | 3 | x | − | 32 |
| = | 9 | x | − | 32 |
| 9 | x | − | 32 | = | 112 |
Transposition :
| 9 | x | = | 112 | + | 32 |
Combine the items on the right of the equation:
| 9 | x | = | 144 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 144 | ÷ | 9 |
| = | 144 | × | 1 9 |
| = | 16 | × | 1 |
We obtained :
| x | = | 16 |
[ 6/6 Equation]
Work: Find the solution of equation ４x×２＋４x－２５ = １１９ .
Question type: Equation
Solution:Original question:
| 4 | x | × | 2 | + | 4 | x | − | 25 | = | 119 |
| Left side of the equation = | 8 | x | + | 4 | x | − | 25 |
| = | 12 | x | − | 25 |
| 12 | x | − | 25 | = | 119 |
Transposition :
| 12 | x | = | 119 | + | 25 |
Combine the items on the right of the equation:
| 12 | x | = | 144 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 144 | ÷ | 12 |
| = | 144 | × | 1 12 |
| = | 12 | × | 1 |
We obtained :
| x | = | 12 |