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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation [2000（1+X）-1000]（1+X） = 1071.25 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
The solution of the equation:
X1≈-1.523385 , keep 6 decimal places
X2≈0.023385 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation [2000（1+X）-1000]（1+X） = 1071.25 .
Question type: Equation
Solution:Original question:
| ( | 2000 | ( | 1 | + | X | ) | − | 1000 | ) | ( | 1 | + | X | ) | = | 4285 4 |
| Left side of the equation = | 2000 | ( | 1 | + | X | ) | ( | 1 | + | X | ) | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | × | 1 | ( | 1 | + | X | ) | + | 2000 | X | ( | 1 | + | X | ) | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | ( | 1 | + | X | ) | + | 2000 | X | ( | 1 | + | X | ) | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | × | 1 | + | 2000 | X | + | 2000 | X | ( | 1 | + | X | ) | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | + | 2000 | X | + | 2000 | X | ( | 1 | + | X | ) | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | + | 2000 | X | + | 2000 | X | × | 1 | + | 2000 | X | X | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | + | 2000 | X | + | 2000 | X | + | 2000 | X | X | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | + | 4000 | X | + | 2000 | X | X | − | 1000 | ( | 1 | + | X | ) |
| = | 2000 | + | 4000 | X | + | 2000 | X | X | − | 1000 | × | 1 | − | 1000 | X |
| = | 2000 | + | 4000 | X | + | 2000 | X | X | − | 1000 | − | 1000 | X |
| = | 1000 | + | 3000 | X | + | 2000 | X | X |
| 1000 | + | 3000 | X | + | 2000 | X | X | = | 4285 4 |
The solution of the equation:
X1≈-1.523385 , keep 6 decimal places
X2≈0.023385 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》