detailed information: The input equation set is: Question solving process:
交After the exchange of equation (1) and equation (2), the equation system becomes:
Divide the two sides of equation (1) by 10, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (6), the equations are reduced to:
Divide the two sides of equation (2) by 10, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
Divide the two sides of equation (2) by 5, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (6), the equations are reduced to:
| | | | | | | | | | 2 5 | C | | - | 8 5 | D | + | | | 7 5 | F | = | | -10 | | (6) |
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Divide the two sides of equation (3) by 4, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (5), the equations are reduced to:
| | | | | | | - | 19 5 | D | | -2 | E | + | | | 1 5 | F | = | | -9 | | (5) |
| | | 2 5 | C | | - | 8 5 | D | + | | | 7 5 | F | = | | -10 | | (6) |
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Divide the two sides of equation (3) by 10, the equation can be obtained: | - | 2 5 | C | + | | | 4 5 | D | + | | | 4 5 | E | = | | 2 | (11) | , then add the two sides of equation (11) to both sides of equation (6), the equations are reduced to:
| | | | | | | - | 19 5 | D | | -2 | E | + | | | 1 5 | F | = | | -9 | | (5) |
| - | 4 5 | D | + | | | 4 5 | E | + | | | 7 5 | F | = | | -8 | | (6) |
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Multiply both sides of equation (4) by 19 Divide the two sides of equation (4) by 5, the equation can be obtained: | - | 19 5 | D | + | | | 19 5 | E | | - | 19 5 | F | = | | 0 | (12) | , then subtract both sides of equation (12) from both sides of equation (5), the equations are reduced to:
| | | | | | | | - | 4 5 | D | + | | | 4 5 | E | + | | | 7 5 | F | = | | -8 | | (6) |
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Multiply both sides of equation (4) by 4 Divide the two sides of equation (4) by 5, the equation can be obtained: | - | 4 5 | D | + | | | 4 5 | E | | - | 4 5 | F | = | | 0 | (13) | , then subtract both sides of equation (13) from both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (6) by 20 Divide both sides of equation (6) by 11, get the equation:, then subtract both sides of equation (14) from both sides of equation (5), get the equation:
Multiply both sides of equation (6) by 5 Divide both sides of equation (6) by 11, get the equation:, then add the two sides of equation (15) to both sides of equation (4), get the equation:
Multiply both sides of equation (6) by 10 Divide both sides of equation (6) by 11, get the equation:, then add the two sides of equation (16) to both sides of equation (2), get the equation:
Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 29, get the equation:, then add the two sides of equation (17) to both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 40 Divide both sides of equation (5) by 29, get the equation:, then add the two sides of equation (18) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 8, get the equation:, then add the two sides of equation (19) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 8, get the equation:, then add the two sides of equation (20) to both sides of equation (2), get the equation:
Subtract both sides of equation (3) from both sides of equation (1), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |