detailed information: The input equation set is: Question solving process:
Multiply both sides of equation (1) by 3 Divide the two sides of equation (1) by 2, the equation can be obtained: | | | 3 | A | + | | | 9 2 | B | | - | 3 2 | C | + | | | 15 2 | D | = | | 0 | (5) | , then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
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Multiply both sides of equation (1) by 2, the equation can be obtained: | | | 4 | A | + | | 6 | B | | -2 | C | + | | 10 | D | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (3), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
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Divide the two sides of equation (1) by 2, the equation can be obtained: | | | A | + | | | 3 2 | B | | - | 1 2 | C | + | | | 5 2 | D | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
| | | - | 3 2 | B | + | | | 9 2 | C | | - | 19 2 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 10 Divide the two sides of equation (2) by 7, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
| | | - | 3 2 | B | + | | | 9 2 | C | | - | 19 2 | D | = | | 0 | | (4) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 7, the equation can be obtained: | | - | 3 2 | B | + | | | 3 2 | C | | - | 87 14 | D | = | | 0 | (9) | , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
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Divide the two sides of equation (3) by 2, the equation can be obtained: , then add the two sides of equation (10) to both sides of equation (4), the equations are reduced to:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 234 Divide both sides of equation (4) by 71, get the equation:, then subtract both sides of equation (11) from both sides of equation (3), get the equation:
 | | | | | - | 7 2 | B | + | | | 7 2 | C | | - | 29 2 | D | = | | 0 | | (2) |
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Multiply both sides of equation (4) by 203 Divide both sides of equation (4) by 71, get the equation:, then add the two sides of equation (12) to both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 70 Divide both sides of equation (4) by 71, get the equation:, then subtract both sides of equation (13) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 7 Divide both sides of equation (3) by 12, get the equation:, then add the two sides of equation (14) to both sides of equation (2), get the equation:
Divide both sides of equation (3) by 6, get the equation:, then subtract both sides of equation (15) from both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 6 Divide both sides of equation (2) by 7, get the equation:, then add the two sides of equation (16) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |