detailed information: The input equation set is:
| | | | -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (3) |
| | | Question solving process:
交After the exchange of equation (1) and equation (3), the equation system becomes:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
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Divide the two sides of equation (1) by 5, the equation can be obtained: | - | 2 5 | A | + | | | 101 1250 | C | + | | | 2 5 | D | + | | | 1 5 | E | = | | | 1 5 | (6) | , then add the two sides of equation (6) to both sides of equation (5), the equations are reduced to:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 101 1250 | C | | - | 3 5 | D | + | | | 1 5 | E | = | | | 1 5 | | (5) |
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Divide the two sides of equation (2) by 3, the equation can be obtained: | -1 | B | + | | | 71 125 | C | + | | | 2 3 | E | = | | 2 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | | 101 1250 | C | | - | 3 5 | D | + | | | 1 5 | E | = | | | 1 5 | | (5) |
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Multiply both sides of equation (3) by 41 Divide the two sides of equation (3) by 250, the equation can be obtained: | | | 41 250 | C | + | | | 41 250 | D | = | | | 41 125 | (8) | , then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | 41 250 | D | | - | 2 3 | E | = | | - | 209 125 | | (4) |
| | | 101 1250 | C | | - | 3 5 | D | + | | | 1 5 | E | = | | | 1 5 | | (5) |
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Multiply both sides of equation (3) by 101 Divide the two sides of equation (3) by 1250, the equation can be obtained: | | | 101 1250 | C | + | | | 101 1250 | D | = | | | 101 625 | (9) | , then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | 41 250 | D | | - | 2 3 | E | = | | - | 209 125 | | (4) |
| - | 851 1250 | D | + | | | 1 5 | E | = | | | 24 625 | | (5) |
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Multiply both sides of equation (4) by 851 Divide the two sides of equation (4) by 205, the equation can be obtained: | | | 851 1250 | D | | - | 1702 615 | E | = | | - | 177859 25625 | (10) | , then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
| | | | 41 250 | D | | - | 2 3 | E | = | | - | 209 125 | | (4) |
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Multiply both sides of equation (5) by 410 Divide both sides of equation (5) by 1579, get the equation: | - | 3158 4737 | E | = | | - | 2830 1579 | (11) | , then subtract both sides of equation (11) from both sides of equation (4), get the equation:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | + | | 2 | E | = | | 6 | | (2) |
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Multiply both sides of equation (5) by 1230 Divide both sides of equation (5) by 1579, get the equation: | - | 3158 1579 | E | = | | - | 8490 1579 | (12) | , then add the two sides of equation (12) to both sides of equation (2), get the equation:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | + | | E | = | | 1 | | (1) |
| -3 | B | + | | | 213 125 | C | = | | | 984 1579 | | (2) |
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Multiply both sides of equation (5) by 615 Divide both sides of equation (5) by 1579, get the equation: | - | 1579 1579 | E | = | | - | 4245 1579 | (13) | , then add the two sides of equation (13) to both sides of equation (1), get the equation:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | = | | - | 2666 1579 | | (1) |
| -3 | B | + | | | 213 125 | C | = | | | 984 1579 | | (2) |
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Multiply both sides of equation (4) by 250 Divide both sides of equation (4) by 41, get the equation:, then subtract both sides of equation (14) from both sides of equation (3), get the equation:
| | | -2 | A | + | | | 101 250 | C | + | | 2 | D | = | | - | 2666 1579 | | (1) |
| -3 | B | + | | | 213 125 | C | = | | | 984 1579 | | (2) |
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Multiply both sides of equation (4) by 500 Divide both sides of equation (4) by 41, get the equation:, then subtract both sides of equation (15) from both sides of equation (1), get the equation:
| | | -2 | A | + | | | 101 250 | C | = | | - | 4982 1579 | | (1) |
| -3 | B | + | | | 213 125 | C | = | | | 984 1579 | | (2) |
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Multiply both sides of equation (3) by 213 Divide both sides of equation (3) by 125, get the equation:, then subtract both sides of equation (16) from both sides of equation (2), get the equation:
| | | -2 | A | + | | | 101 250 | C | = | | - | 4982 1579 | | (1) |
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Multiply both sides of equation (3) by 101 Divide both sides of equation (3) by 250, get the equation:, then subtract both sides of equation (17) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |