detailed information: The input equation set is: Question solving process:
Subtract both sides of equation (1) from both sides of equation (4) ,the equations are reduced to:
Multiply both sides of equation (1) by 10, the equation can be obtained: , then subtract both sides of equation (7) from both sides of equation (5), the equations are reduced to:
Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
Multiply both sides of equation (2) by 20, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
 | | | | | | | -20 | C | + | | 24 | D | + | | 10 | F | = | | -20 | | (5) |
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Add both sides of equation (3) to both sides of equation (4) ,the equations are reduced to:
 | | | | | | | -20 | C | + | | 24 | D | + | | 10 | F | = | | -20 | | (5) |
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Multiply both sides of equation (3) by 20, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (3) by 8, the equation can be obtained: , then add the two sides of equation (10) to both sides of equation (6), the equations are reduced to:
交After the exchange of equation (4) and equation (5), the equation system becomes:
Divide the two sides of equation (4) by 6, the equation can be obtained: | | 4 | D | + | | | 10 3 | E | | - | 5 3 | F | = | | - | 10 3 | (11) | , then add the two sides of equation (11) to both sides of equation (6), the equations are reduced to:
交After the exchange of equation (5) and equation (6), the equation system becomes:
Multiply both sides of equation (5) by 30 Divide both sides of equation (5) by 29, get the equation:, then subtract both sides of equation (12) from both sides of equation (4), get the equation:
Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 58, get the equation:, then subtract both sides of equation (13) from both sides of equation (3), get the equation:
Divide both sides of equation (4) by 24, get the equation:, then add the two sides of equation (14) to both sides of equation (2), get the equation:
Subtract both sides of equation (3) from both sides of equation (2), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: F are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |