detailed information: The input equation set is:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | -2 | A | | - | 1 2 | B | | - | 1 2 | D | | -2 | E | = | | -1 | | (3) |
| | | -16 | A | | -1 | B | | -1 | D | | -16 | E | = | | 0 | | (5) |
| Question solving process:
Multiply both sides of equation (1) by 2, the equation can be obtained: | | | 2 | A | + | | 2 | B | + | | 2 | C | + | | 2 | D | + | | 2 | E | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | -2 | A | | - | 1 2 | B | | - | 1 2 | D | | -2 | E | = | | -1 | | (3) |
| | | -16 | A | | -1 | B | | -1 | D | | -16 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 2, the equation can be obtained: | | | 2 | A | + | | 2 | B | + | | 2 | C | + | | 2 | D | + | | 2 | E | = | | 0 | (7) | , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | | -16 | A | | -1 | B | | -1 | D | | -16 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 8, the equation can be obtained: | | | 8 | A | + | | 8 | B | + | | 8 | C | + | | 8 | D | + | | 8 | E | = | | 0 | (8) | , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | | -16 | A | | -1 | B | | -1 | D | | -16 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 16, the equation can be obtained: | | | 16 | A | + | | 16 | B | + | | 16 | C | + | | 16 | D | + | | 16 | E | = | | 0 | (9) | , then add the two sides of equation (9) to both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 2, the equation can be obtained: | | - | 3 2 | B | | -3 | C | | - | 9 2 | D | | -6 | E | = | | 0 | (10) | , then add the two sides of equation (10) to both sides of equation (3), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (2) by 7, the equation can be obtained: | | -7 | B | | -14 | C | | -21 | D | | -28 | E | = | | 0 | (11) | , then subtract both sides of equation (11) from both sides of equation (4), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (2) by 15, the equation can be obtained: | | -15 | B | | -30 | C | | -45 | D | | -60 | E | = | | 0 | (12) | , then add the two sides of equation (12) to both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (3) by 6, the equation can be obtained: , then add the two sides of equation (13) to both sides of equation (4), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (3) by 14, the equation can be obtained: | | -14 | C | | -42 | D | | -84 | E | = | | -14 | (14) | , then subtract both sides of equation (14) from both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Multiply both sides of equation (4) by 2, the equation can be obtained: , then add the two sides of equation (15) to both sides of equation (5), the equations are reduced to:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Subtract both sides of equation (5) from both sides of equation (4), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Divide both sides of equation (5) by 4, get the equation:, then subtract both sides of equation (16) from both sides of equation (3), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Divide both sides of equation (5) by 6, get the equation:, then subtract both sides of equation (17) from both sides of equation (2), get the equation:
 | | | | | A | + | | B | + | | C | + | | D | + | | E | = | | 0 | | (1) |
| | | | |
Divide both sides of equation (5) by 24, get the equation:, then add the two sides of equation (18) to both sides of equation (1), get the equation:
Divide both sides of equation (4) by 2, get the equation:, then subtract both sides of equation (19) from both sides of equation (3), get the equation:
Divide both sides of equation (4) by 2, get the equation:, then subtract both sides of equation (20) from both sides of equation (2), get the equation:
Divide both sides of equation (4) by 6, get the equation:, then add the two sides of equation (21) to both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 2, get the equation:, then subtract both sides of equation (22) from both sides of equation (2), get the equation:
Add both sides of equation (3) to both sides of equation (1), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |